使用 Jasmine 监视函数中的变量

问题描述

假设我有如下函数

function fun1(a) {
  var local_a = a;
  local_a += 5;
  return local_a/2;
}

有没有办法测试 local_a 的值是什么(例如在第一行代码中)?我对茉莉花有点陌生，所以我被卡住了.提前致谢.

Is there a way to test for the value of local_a being what it should be (for example in the first line of code)? I'm a bit new to Jasmine, so am stuck. Thanks in advance.

推荐答案

不是.不过，您可以执行以下操作:

Not really. You can do the following though:

测试fun1()的结果:

expect(fun1(5)).toEqual(5);

确保它被实际调用(如果它通过事件发生则很有用)并测试结果:

Make sure it's actually called (useful if it happens through events) and also test the result:

var spy = jasmine.createSpy(window, 'fun1').andCallThrough();
fire_event_calling_fun1();
expect(spy).toHaveBeenCalled();
expect(some_condition);

真正重现检查中间结果的整个功能:

Really reproduce the whole function inspecting intermediate results:

var spy = jasmine.createSpy(window, 'fun1').andCallFake(function (a) {
  var local_a = a;
  expect(local_a).toEqual(a);
  local_a += 5;
  expect(local_a).toEqual(a+5);
  return local_a/2;
});
fun1(42);
expect(spy).toHaveBeenCalled();

这篇关于使用 Jasmine 监视函数中的变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！