在测试期间我需要做以下事情:
During test I need to do following:
我的代码:
$this->byId('reg_email')->value('test@example.com');
$this->byId('reg_password')->value('seecret');
// No form here, so i can't just call submit()
// This click invokes ajax request
$this->byId('reg_submit')->click();
// Check page content (this page should appear after redirect)
$msg = $this->byCssSelector('h1')->text();
$this->assertEquals('Welcome!', $msg);
问题
解决办法,我不喜欢:
sleep(3);
.我不喜欢它,因为:
我想知道,有没有什么方法可以跟踪 ajax 请求+刷新并及时检查内容?
I wonder, is there any way to track ajax request+refresh and check for content just in time?
我的设置:
好吧,有一种解决方案,我不是很喜欢它,但它是有的而不是无.
Ok, there is a kind of solution, I do not really like it, but it is something instead of nothing.
这个想法是使用更智能的睡眠",有一个方法 waitUntil()
采用 anonymous function
和 timeout
in毫秒.什么是 - 在循环中运行这个传递的函数,直到超时或你的函数返回 True
.所以你可以运行一些东西并等到上下文改变:
The idea is to use more smart "sleep", there is a method waitUntil()
which takes an anonymous function
and timeout
in milliseconds. What is does - runs this passed function in loop until timeout hits or your function return True
. So you can run something and wait until context is changed:
$this->waitUntil(function () {
if ($this->byCssSelector('h1')) {
return true;
}
return null;
}, 5000);
如果有人提供更好的解决方案,我仍然会很高兴.
I still will be glad if somebody give better solution.
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