我几乎是加密新手.
我正在尝试解密一个字节数组,当我提供 IV 时,我遇到了一个异常:InvalidAlgorithmParameterException(预期时未设置 iv).
I am trying to decrypt an array of bytes, and when I am providing the IV I am getting an exception : InvalidAlgorithmParameterException (no iv set when one expected).
这是我的代码(iv 是一个 16 字节的数组,它不为空,并且具有加密时使用的值):
Here's my code (iv is an array of 16 bytes which is not null and has the values used when encrypting) :
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, encriptionKey,new IvParameterSpec(iv));
如果我没有指定 IV,密码会被初始化:
If I don't specify the IV the cipher gets initialized ok :
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, encriptionKey);
试图找到答案,我确实找到了 JCEStreamCipher 的实现(here) 这可能与我使用的版本不对应,但有一些代码让我觉得我没有正确理解它.
Trying to find an answer I did find an implementation of JCEStreamCipher (here) which may not correspond to the version I am using but has some code that makes me thing I am not understanding it correctly.
代码如下:
if ((ivLength != 0) && !(param instanceof ParametersWithIV))
{
SecureRandom ivRandom = random;
if (ivRandom == null)
{
ivRandom = new SecureRandom();
}
if ((opmode == Cipher.ENCRYPT_MODE) || (opmode == Cipher.WRAP_MODE))
{
byte[] iv = new byte[ivLength];
ivRandom.nextBytes(iv);
param = new ParametersWithIV(param, iv);
ivParam = (ParametersWithIV)param;
}
else
{
throw new InvalidAlgorithmParameterException("no IV set when one expected");
}
}
看起来我在解密时无法提供 IV,但这对我来说没有太大意义.
Looks like I cannot provide an IV when decrypting, but it doesn't makes too much sense to me.
任何帮助将不胜感激.
非常感谢,理查德.
已解决.
我使用了错误的 SecretKey,而不是您可以为 AES 创建的密钥.
I was using a wrong SecretKey, not the one you can create for AES.
以前我有:
KeySpec spec = new PBEKeySpec(password.toCharArray(), encryptionKeySalt, 12345,256);
SecretKey encriptionKey = factory.generateSecret(spec);
创建一个 JCEPBEKey.
which creates a JCEPBEKey.
我失踪了:
Key encriptionKey = new SecretKeySpec(encriptionKey.getEncoded(), "AES");
为 AES 创建一个适当的密钥.
which creates an appropiate key for AES.
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