按天分组的 SQL 查询

问题描述

我想列出所有销售额，并按天分组.

I want to list all sales, and group the sum by day.

Sales (saleID INT, amount INT, created DATETIME)

注意:我使用的是 SQL Server 2005.

NOTE: I am using SQL Server 2005.

推荐答案

如果您使用的是 SQL Server，

if you're using SQL Server,

dateadd(DAY,0, datediff(day,0, created)) 将返回创建日期

例如，如果销售创建于2009-11-02 06:12:55.000"，dateadd(DAY,0, datediff(day,0, created)) return '2009-11-02 00:00:00.000'

for example, if the sale created on '2009-11-02 06:12:55.000', dateadd(DAY,0, datediff(day,0, created)) return '2009-11-02 00:00:00.000'

select sum(amount) as total, dateadd(DAY,0, datediff(day,0, created)) as created
from sales
group by dateadd(DAY,0, datediff(day,0, created))

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