我想在下面的 SQL 中显示列 B
,但是当我将它添加到查询中时,它给了我以下错误:
T2.B' 列在选择列表中无效,因为它不包含在聚合函数或 GROUP BY 子句.
我的代码:
SELECT A, COUNT(B) as T1, B从 T2哪里 ID=1按 A 分组
换句话说,这个错误告诉你SQL Server不知道哪个 B
从组中选择.
无论您想选择一个特定的值(例如 MIN
、SUM
或 AVG
),在这种情况下,您都可以使用适当的聚合函数,或者您想选择每个值作为新行(即在 GROUP BY
字段列表中包含 B
).
考虑以下数据:
<前>身份证号1 1 131 1 791 2 131 2 131 2 42查询
SELECT A, COUNT(B) AS T1从 T2按 A 分组
会回来:
<前>一个 T11 22 3一切都很好.
但是,请考虑以下(非法)查询,这会产生此错误:
SELECT A, COUNT(B) AS T1, B从 T2按 A 分组
及其返回的说明问题的数据集:
<前>A T1 B1 2 13?79?13 和 79 作为单独的行?(13+79=92)?……?2 3 13?42?……?<小时>
但是,以下两个查询说明了这一点,不会导致错误:
使用聚合
SELECT A, COUNT(B) AS T1, SUM(B) AS B从 T2按 A 分组
会回来:
<前>A T1 B1 2 922 3 68将列添加到GROUP BY
列表
SELECT A, COUNT(B) AS T1, B从 T2按 A、B 分组
会回来:
<前>A T1 B1 1 131 1 792 2 132 1 42I would like to display the column B
in my below SQL, but when I add it to the query it gives me the following error:
Column T2.B' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
My code:
SELECT A, COUNT(B) as T1, B
FROM T2
WHERE ID=1
GROUP BY A
Put in other words, this error is telling you that SQL Server does not know which B
to select from the group.
Either you want to select one specific value (e.g. the MIN
, SUM
, or AVG
) in which case you would use the appropriate aggregate function, or you want to select every value as a new row (i.e. including B
in the GROUP BY
field list).
Consider the following data:
ID A B 1 1 13 1 1 79 1 2 13 1 2 13 1 2 42
The query
SELECT A, COUNT(B) AS T1
FROM T2
GROUP BY A
would return:
A T1 1 2 2 3
which is all well and good.
However consider the following (illegal) query, which would produce this error:
SELECT A, COUNT(B) AS T1, B
FROM T2
GROUP BY A
And its returned data set illustrating the problem:
A T1 B 1 2 13? 79? Both 13 and 79 as separate rows? (13+79=92)? ...? 2 3 13? 42? ...?
However, the following two queries make this clear, and will not cause the error:
Using an aggregate
SELECT A, COUNT(B) AS T1, SUM(B) AS B
FROM T2
GROUP BY A
would return:
A T1 B 1 2 92 2 3 68
Adding the column to the GROUP BY
list
SELECT A, COUNT(B) AS T1, B
FROM T2
GROUP BY A, B
would return:
A T1 B 1 1 13 1 1 79 2 2 13 2 1 42
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