我发现 std::set
上的更新操作很乏味,因为 cppreference.所以我目前做的是这样的:
I find the update operation on std::set
tedious since there's no such an API on cppreference. So what I currently do is something like this:
//find element in set by iterator
Element copy = *iterator;
... // update member value on copy, varies
Set.erase(iterator);
Set.insert(copy);
基本上Set
返回的迭代器是一个const_iterator
,你不能直接改变它的值.
Basically the iterator return by Set
is a const_iterator
and you can't change its value directly.
有没有更好的方法来做到这一点?或者也许我应该通过创建我自己的来覆盖 std::set
(我不知道它究竟是如何工作的......)
Is there a better way to do this? Or maybe I should override std::set
by creating my own (which I don't know exactly how it works..)
set
返回 const_iterators
(标准说set
code> 是 const
,并且 set
和 set
实际上可能是同一类型- 请参阅 n3000.pdf 中的 23.2.4/6),因为它是一个有序容器.如果它返回一个常规的 iterator
,您将被允许从容器下更改 items 值,这可能会改变排序.
set
returns const_iterators
(the standard says set<T>::iterator
is const
, and that set<T>::const_iterator
and set<T>::iterator
may in fact be the same type - see 23.2.4/6 in n3000.pdf) because it is an ordered container. If it returned a regular iterator
, you'd be allowed to change the items value out from under the container, potentially altering the ordering.
您的解决方案是更改set
中的项目的惯用方法.
Your solution is the idiomatic way to alter items in a set
.
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