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        CoffeeScript - 无与伦比的 OUTDENT

        时间:2024-04-19

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                  本文介绍了CoffeeScript - 无与伦比的 OUTDENT的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我一直在尝试将我的工作 javascript 代码传递给 CoffeeScript,但我无法通过此错误:

                  I've been trying to pass my working javascript code into CoffeeScript but i can't get pass this error:

                  第 55 行不匹配的 OUTDENT

                  unmatched OUTDENT on line 55

                  这是咖啡脚本代码

                  $(document).on("click",".save_button", ->
                      $form = $(this).parent().parent().parent().parent().parent().parent()
                      $form.bind("ajax:complete", ->
                                  $actionURI = $form.attr("action");
                          $.get(window.location.protocol+"//"+window.location.host+$actionURI+".js",(data) ->
                                      $form.parent().parent().prev().html(data); //Line 55
                                      closeSaveElement()
                          ,"html")
                      );
                      $form.submit();   
                      return false;
                  );
                  

                  我已经尝试在任何地方放置和擦除 ; 但我没有什么问题.我也尝试将 -> 更改为 => 但弹出相同的错误.

                  i've tried putting and erasing ; everywhere but i don't whats wrong. I also tried to change -> for => but the same error pops up.

                  推荐答案

                  有效的 JS 并不是真正有效的 CoffeeScript.你必须这样做:

                  Valid JS isn't really valid CoffeeScript. You'd have to do something like this:

                  $(document).on "click", ".save_button", ->
                      $form = $(this).parent().parent().parent().parent().parent().parent()
                  
                      $form.bind "ajax:complete", ->
                          $actionURI = $form.attr "action"
                          $.ajax
                              type: "get"
                              url: "#{window.location.protocol}//#{window.location.host}#{$actionURI}.js"
                              dataType: "html"
                              success: ->
                                  $form.parent().parent().prev().html(data)
                                  closeSaveElement()
                  
                      $form.submit()
                  
                      return false
                  

                  另外,对这一行做点什么:

                  Also, do something about this line:

                  $form = $(this).parent().parent().parent().parent().parent().parent()
                  

                  .closest() 应该会有所帮助.

                  这篇关于CoffeeScript - 无与伦比的 OUTDENT的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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