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    1. 对具有匹配值的 JSON 键进行排序和合并

      时间:2024-04-19

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                本文介绍了对具有匹配值的 JSON 键进行排序和合并的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                我的 JSON 如下所示:

                My JSON looks like this:

                json = [
                  {
                    type: "big"
                    date: "2012-12-08"
                    qty: 6
                  }
                  {
                    type: "small"
                    date: "2012-12-08"
                    qty: 9
                  }
                  {
                    type: "big"
                    date: "2012-12-15"
                    qty: 4
                  }
                  {
                    type: "small"
                    date: "2012-12-07"
                    qty: 7
                  }
                  {
                    type: "small"
                    date: "2012-11-07"
                    qty: 3
                  }
                ]    
                

                我想要做的是分组/合并每个 type 具有相同年份的 date &月(date 字符串中的前 7 个字符)并获取这些 qty 的总和.输出应如下所示:

                What I'm trying to do is group/merge each type that has a date with the same year & month (the first 7 characters in the date string) and get the sum of those qty's. The output should look like this:

                json = [
                  {
                    type: "big"
                    date: "2012-12"
                    qty: 10
                  }
                  {
                    type: "small"
                    date: "2012-12"
                    qty: 16
                  }
                  {
                    type: "small"
                    date: "2012-11"
                    qty: 3
                  }
                ]  
                

                我在这里找到了几个类似的问题,但没有遇到一个完全符合我要求的问题.我玩过很多从不同示例中借来的代码,但似乎无法得到我需要的结果.我现在不在家,因此我目前无法粘贴任何我尝试过的代码,但我正在寻求帮助,希望得到答案/解决方案以便稍后测试

                There are several similar questions I've found here but haven't come across one that does exactly what I'm looking for. I have played around with lots of code borrowed from different examples but can't quite seem to get the results I need. I'm not home now, therefore I can't paste any code I've tried at the moment but I'm asking for help in hopes to have an answer/solution to test out later

                推荐答案

                这很容易通过创建一个自定义对象来处理,该对象具有以您的唯一组合命名的属性(即类型 + 日期的前 7 个).

                This is easily handled by creating a custom object that has properties named with your unique combinations (i.e. type + first 7 of date).

                遍历您的数组并检查您的持有人"对象是否具有以您的唯一标识符命名的现有属性.如果它已经具有该属性,则增加数量,否则添加一个新项目.

                Loop through your array and check if your "holder" object has an existing property named with your unique identifier. If it has the property already, then increment the quantity, otherwise add a new item.

                在完全构建完持有人后,清除您的数组,然后循环浏览持有人的属性并将它们推回您的数组.

                After the holder is completely built, clear your array, then loop through the properties of the holder and push them back on to your array.

                var holder = {};
                var json = [
                  {
                    type: "big",
                    date: "2012-12-08",
                    qty: 6
                  },
                  {
                    type: "small",
                    date: "2012-12-08",
                    qty: 9
                  },
                  {
                    type: "big",
                    date: "2012-12-15",
                    qty: 4
                  },
                  {
                    type: "small",
                    date: "2012-12-07",
                    qty: 7
                  },
                  {
                    type: "small",
                    date: "2012-11-07",
                    qty: 3
                  }
                ];
                
                json.forEach(function(element) {
                  var identifier = element.type + element.date.slice(0, 7);
                  if (holder[identifier]) {
                    holder[identifier].qty += element.qty;
                  } else {
                    holder[identifier] = element;
                  };
                });
                
                json = [];
                for(var identifier in holder) {
                  json.push(holder[identifier]);
                }
                
                console.log(json);

                这篇关于对具有匹配值的 JSON 键进行排序和合并的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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