funName = () ->
$(".foo").addClass("bar");
Compiles into the scope of an anonymous function. Calling funName
from the console results in undefined
.
(function() {
var funName;
funName = function() {
return $(".foo").addClass("bar");
};
}).call(this);
What's its reasoning for compiling like this and how do I work with it?
Also any insight on the mandatory return within functions using CoffeeScript would be great. Why is it like that? How do I need to code differently because of it?
Mike has answered the main question here. The modular wrapper a common point of confusion for CoffeeScript newcomers, as illustrated by these related questions:
As to your other question: If you don't want a function to return anything, simply make the last line of that function either return
by itself or, equivalently, undefined
. Either will compile to a function with no return
. For instance:
funName = ->
$(".foo").addClass "bar"
return
compiles to
var funName;
funName = function() {
$(".foo").addClass("bar");
};
Note that there is an ongoing discussion (issue 899) about a possible alternative syntax for defining no-return functions. If the current proposal were accepted, you'd be able to write your function as
funName = -/> $(".foo").addClass "bar"
If you like that syntax, you should voice your support for it.
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