<tfoot id='Uikji'></tfoot>
      <legend id='Uikji'><style id='Uikji'><dir id='Uikji'><q id='Uikji'></q></dir></style></legend>
      <i id='Uikji'><tr id='Uikji'><dt id='Uikji'><q id='Uikji'><span id='Uikji'><b id='Uikji'><form id='Uikji'><ins id='Uikji'></ins><ul id='Uikji'></ul><sub id='Uikji'></sub></form><legend id='Uikji'></legend><bdo id='Uikji'><pre id='Uikji'><center id='Uikji'></center></pre></bdo></b><th id='Uikji'></th></span></q></dt></tr></i><div id='Uikji'><tfoot id='Uikji'></tfoot><dl id='Uikji'><fieldset id='Uikji'></fieldset></dl></div>
    1. <small id='Uikji'></small><noframes id='Uikji'>

          <bdo id='Uikji'></bdo><ul id='Uikji'></ul>

        jQuery 推送堆栈

        时间:2023-10-20

        <i id='7PDBo'><tr id='7PDBo'><dt id='7PDBo'><q id='7PDBo'><span id='7PDBo'><b id='7PDBo'><form id='7PDBo'><ins id='7PDBo'></ins><ul id='7PDBo'></ul><sub id='7PDBo'></sub></form><legend id='7PDBo'></legend><bdo id='7PDBo'><pre id='7PDBo'><center id='7PDBo'></center></pre></bdo></b><th id='7PDBo'></th></span></q></dt></tr></i><div id='7PDBo'><tfoot id='7PDBo'></tfoot><dl id='7PDBo'><fieldset id='7PDBo'></fieldset></dl></div>

          <tfoot id='7PDBo'></tfoot>
        • <legend id='7PDBo'><style id='7PDBo'><dir id='7PDBo'><q id='7PDBo'></q></dir></style></legend>
                <tbody id='7PDBo'></tbody>
                <bdo id='7PDBo'></bdo><ul id='7PDBo'></ul>
              • <small id='7PDBo'></small><noframes id='7PDBo'>

                  本文介绍了jQuery 推送堆栈的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我需要一些帮助来理解 pushStack

                  I need some help to understand pushStack

                  这里我做了一个例子,使用与否的结果是一样的http://jsfiddle.net/Bz5n9/2/ 所以我想我真的不明白它的用途.

                  Here I've made an example where the results using it or not are the same http://jsfiddle.net/Bz5n9/2/ so I think i really didn't get what is it for.

                  谢谢!

                  推荐答案

                  您当前正在添加到集合中,将一个新集合推送到堆栈上,该集合已经是结果(您可以只返回 this.添加()).它所做的不是将 .b 元素作为新元素推送到堆栈上,而是推送带有 .b 元素 的新集合#2 <li> 你开始用的.

                  You're currently adding to the collection, pushing a new collection on the stack that's already the result (you could just return the result of this.add()). What this does is instead of pushing .b elements on the stack as a new element, it pushes a new set with .b elements and the #2 <li> you started with.

                  相反,您应该直接传递元素(没有 .add() 调用),像这样:

                  Instead, you instead should pass the elements directly (no .add() call), like this:

                  return this.pushStack(newCollection, "agregate", "");
                  

                  你可以在这里测试一下.

                  这篇关于jQuery 推送堆栈的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

                  上一篇:存储在堆栈上的 Javascript 字符串 下一篇:使用 javascript 确定 javascript 中的堆栈深度

                  相关文章

                  • <bdo id='d9deB'></bdo><ul id='d9deB'></ul>
                • <i id='d9deB'><tr id='d9deB'><dt id='d9deB'><q id='d9deB'><span id='d9deB'><b id='d9deB'><form id='d9deB'><ins id='d9deB'></ins><ul id='d9deB'></ul><sub id='d9deB'></sub></form><legend id='d9deB'></legend><bdo id='d9deB'><pre id='d9deB'><center id='d9deB'></center></pre></bdo></b><th id='d9deB'></th></span></q></dt></tr></i><div id='d9deB'><tfoot id='d9deB'></tfoot><dl id='d9deB'><fieldset id='d9deB'></fieldset></dl></div>

                    <tfoot id='d9deB'></tfoot>
                    <legend id='d9deB'><style id='d9deB'><dir id='d9deB'><q id='d9deB'></q></dir></style></legend>
                    1. <small id='d9deB'></small><noframes id='d9deB'>