我创建了一个 静态网站 托管在 AWS s3 存储桶上.
I made a static website hosted on an AWS s3 bucket.
我不了解有关 Web 开发的工具和技术,但我举了一个 index.html 代码示例,该代码允许我从名为my_data_file1.csv"的单个文件中绘制数据.
I do not know the tools and technology around web development, but I took an example of index.html code allowing me to plot data from a single file named "my_data_file1.csv".
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<meta http-equiv="X-UA-Compatible" content="ie=edge" />
<title>Coding Train: Data and APIs Project 1</title>
<script src="https://cdn.jsdelivr.net/npm/chart.js@2.8.0"></script>
</head>
<body>
<h1>Global Temperatures</h1>
<canvas id="myChart" width="400" height="200"></canvas>
<script>
window.addEventListener('load', setup);
async function setup() {
const ctx = document.getElementById('myChart').getContext('2d');
const globalTemps = await getData();
const myChart = new Chart(ctx, {
type: 'line',
data: {
labels: globalTemps.years,
datasets: [
{
label: 'Temperature in °C',
data: globalTemps.temps,
fill: false,
borderColor: 'rgba(255, 99, 132, 1)',
backgroundColor: 'rgba(255, 99, 132, 0.5)',
borderWidth: 1
}
]
},
options: {}
});
}
async function getData() {
const response = await fetch('my_data_file1.csv');
const data = await response.text();
const years = [];
const temps = [];
const rows = data.split('
').slice(1);
rows.forEach(row => {
const cols = row.split(',');
years.push(cols[0]);
temps.push(parseFloat(cols[2]));
});
return { years, temps };
}
</script>
</body>
</html>
我的所有数据都拆分为多个文件,因此我希望能够说明一个目录中的所有 CSV 文件,而不仅仅是一个.我的文件名是可变的,所以我不能一一列出.是否可以将过滤器或正则表达式用作*.csv"?提前致谢,
All of my data is split into multiple files, so I would like to be able to account for all the CSV files in a directory, rather than just one. The name of my files is variable, so I cannot list them one by one. Is it possible to use a filter or RegEx as "*.csv"? Thanks in advance,
是否可以将过滤器或 RegEx 用作*.csv"?
Is it possible to use a filter or RegEx as "*.csv"?
没有.
虽然可以通过将文件和目录从文件系统映射到 URL,生成 URL,但 URL 不是目录.
While URLs can be generated by mapping files and directories from a filesystem to URLs, a URL isn't a directory.
没有办法glob URL.
您可以确保服务器在请求 ./
时返回一个 URL 列表,然后使用客户端 JS 对其进行解析和过滤,然后请求每个 URL(可能使用 Promise.all
来确定您何时对这些请求中的每一个都有响应).
You could ensure that the server, when asked for ./
returns a list of URLs and then parse and filter it with client-side JS, and then request each of those URLs (probably using Promise.all
to determine when you had a response for every one of those requests).
您还可以编写服务器端代码来连接所有 CSV 数据,这样您只需发出一个请求.
You could also write server-side code to concatenate all the CSV data so you only have to make one request.
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