我正在尝试在Python中找到正确的方式来完成以下任务(这不是按书面方式工作的):
myList = ["a", "b", "c"]
myCounter = 5
for item in myList:
print("""Really long text
in which I need to put the next iteration of myCounter (""", myCounter++, """) followed
by a lot more text with many line breaks
followed by the next iteration of myCounter (""", myCounter++, """) followed by even
more long text until finally we get to the next
iteration of the for loop.""", sep='')
不幸的是(至少对我而言),Python中不存在++运算符或语句作为将变量递增1的方式,而是使用
myCounter += 1
当我想要打印变量并同时递增它时,
似乎也不起作用。我希望它第一次通过for循环打印5和6,然后在下一次打印7和8,最后一次打印9和10。在Python3中应如何完成此操作?
我可能会考虑使用itertools.count
:
import itertools
myCounter = itertools.count(5)
for item in myList:
print("la la la.", next(myCounter), "foo foo foo", next(myCounter))
如果您希望避免导入,也可以很容易地编写自己的生成器来做这类事情:
def counter(val=0):
while True:
yield val
val += 1
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