有没有办法在Python的subprocess.Popen()
中指定命令的运行目录?
Is there a way to specify the running directory of command in Python's subprocess.Popen()
?
例如:
Popen('c:mytool ool.exe', workingdir='d: estlocal')
我的 Python 脚本位于 C:programspython
My Python script is located in C:programspython
是否可以在D: estlocal
目录下运行C:mytool ool.exe
?
Is is possible to run C:mytool ool.exe
in the directory D: estlocal
?
如何设置子进程的工作目录?
How do I set the working directory for a sub-process?
subprocess.Popen
采用 cwd
参数 来设置当前工作目录;您还需要转义反斜杠 ('d:\test\local'
),或使用 r'd: estlocal'
以便Python 不会将反斜杠解释为转义序列.按照您编写的方式,
部分将被转换为 tab.
subprocess.Popen
takes a cwd
argument to set the Current Working Directory; you'll also want to escape your backslashes ('d:\test\local'
), or use r'd: estlocal'
so that the backslashes aren't interpreted as escape sequences by Python. The way you have it written, the
part will be translated to a tab.
所以,你的新行应该是这样的:
So, your new line should look like:
subprocess.Popen(r'c:mytool ool.exe', cwd=r'd: estlocal')
<小时>
要将 Python 脚本路径用作 cwd,import os
并使用以下命令定义 cwd:
To use your Python script path as cwd, import os
and define cwd using this:
os.path.dirname(os.path.realpath(__file__))
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