我了解如何在 for 循环中使用 range()
和 zip()
等函数.但是我希望 range()
输出一个列表 - 很像 unix shell 中的 seq
.如果我运行以下代码:
I understand how functions like range()
and zip()
can be used in a for loop. However I expected range()
to output a list - much like seq
in the unix shell. If I run the following code:
a=range(10)
print(a)
输出是range(10)
,表明它不是一个列表,而是一种不同类型的对象.zip()
在打印时有类似的行为,输出类似
The output is range(10)
, suggesting it's not a list but a different type of object. zip()
has a similar behaviour when printed, outputting something like
<zip object at "hexadecimal number">
所以我的问题是它们是什么,制作它们有什么优势,以及如何在不循环它们的情况下将它们的输出输出到列表?
So my question is what are they, what advantages are there to making them this, and how can I get their output to lists without looping over them?
你必须使用 Python 3.
You must be using Python 3.
在 Python 2 中,对象 zip
和 range
确实按照您的建议行事,返回列表.它们已更改为类似 generator 的对象,这些对象按需生成元素,而不是将整个列表扩展为记忆.一个优势是在它们的典型用例中效率更高(例如迭代它们).
In Python 2, the objects zip
and range
did behave as you were suggesting, returning lists. They were changed to generator-like objects which produce the elements on demand rather than expand an entire list into memory. One advantage was greater efficiency in their typical use-cases (e.g. iterating over them).
惰性"版本也存在于 Python 2.x 中,但它们有不同的名称,即 xrange
和 itertools.izip
.
The "lazy" versions also exist in Python 2.x, but they have different names i.e. xrange
and itertools.izip
.
要一次将所有输出检索到熟悉的列表对象中,您可以简单地调用 list
来迭代并使用内容:
To retrieve all the output at once into a familiar list object, you may simply call list
to iterate and consume the contents:
>>> list(range(3))
[0, 1, 2]
>>> list(zip(range(3), 'abc'))
[(0, 'a'), (1, 'b'), (2, 'c')]
这篇关于Python range() 和 zip() 对象类型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!