带虚线或虚线的opencv矩形

时间:2022-11-19
本文介绍了带虚线或虚线的opencv矩形的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我这里有一行代码使用了opencv的python绑定:

I have a line of code here that uses the python binding for opencv:

cv2.rectangle(img, (box[1], box[0]), (box[3], box[2]), (255,0,0), 4)

这会在厚度为 4 的图像 img 上绘制一个红色矩形.

This draws a red rectangle on image img of thickness 4.

但是有没有办法可以对矩形的线条进行风格化?没有太多.只是点缀或虚线,就是这样.

But is there a way the lines of the rectangles can be stylized? Not too much. Just dotted, or dashed, that's it really.

推荐答案

import cv2
import numpy as np
def drawline(img,pt1,pt2,color,thickness=1,style='dotted',gap=20):
    dist =((pt1[0]-pt2[0])**2+(pt1[1]-pt2[1])**2)**.5
    pts= []
    for i in  np.arange(0,dist,gap):
        r=i/dist
        x=int((pt1[0]*(1-r)+pt2[0]*r)+.5)
        y=int((pt1[1]*(1-r)+pt2[1]*r)+.5)
        p = (x,y)
        pts.append(p)

    if style=='dotted':
        for p in pts:
            cv2.circle(img,p,thickness,color,-1)
    else:
        s=pts[0]
        e=pts[0]
        i=0
        for p in pts:
            s=e
            e=p
            if i%2==1:
                cv2.line(img,s,e,color,thickness)
            i+=1

def drawpoly(img,pts,color,thickness=1,style='dotted',):
    s=pts[0]
    e=pts[0]
    pts.append(pts.pop(0))
    for p in pts:
        s=e
        e=p
        drawline(img,s,e,color,thickness,style)

def drawrect(img,pt1,pt2,color,thickness=1,style='dotted'):
    pts = [pt1,(pt2[0],pt1[1]),pt2,(pt1[0],pt2[1])] 
    drawpoly(img,pts,color,thickness,style)

im = np.zeros((800,800,3),dtype='uint8')
s=(234,222)
e=(500,700)
drawrect(im,s,e,(0,255,255),1,'dotted')

cv2.imshow('im',im)
cv2.waitKey()      

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