我有一个列表abc"和一个数据框df":
I have a list 'abc' and a dataframe 'df':
abc = ['foo', 'bar']
df =
A B
0 12 NaN
1 23 NaN
我想将列表插入单元格 1B,所以我想要这个结果:
I want to insert the list into cell 1B, so I want this result:
A B
0 12 NaN
1 23 ['foo', 'bar']
我可以这样做吗?
1) 如果我使用这个:
1) If I use this:
df.ix[1,'B'] = abc
我收到以下错误消息:
ValueError: Must have equal len keys and value when setting with an iterable
因为它试图将列表(包含两个元素)插入行/列而不是单元格.
because it tries to insert the list (that has two elements) into a row / column but not into a cell.
2) 如果我使用这个:
2) If I use this:
df.ix[1,'B'] = [abc]
然后它会插入一个列表,其中只有一个元素是 'abc' 列表( [['foo', 'bar']]
).
then it inserts a list that has only one element that is the 'abc' list ( [['foo', 'bar']]
).
3) 如果我使用这个:
3) If I use this:
df.ix[1,'B'] = ', '.join(abc)
然后它插入一个字符串:( foo, bar
) 但不是一个列表.
then it inserts a string: ( foo, bar
) but not a list.
4) 如果我使用这个:
4) If I use this:
df.ix[1,'B'] = [', '.join(abc)]
然后它插入一个列表,但它只有一个元素( ['foo, bar']
)但不是我想要的两个( ['foo', 'bar']
).
then it inserts a list but it has only one element ( ['foo, bar']
) but not two as I want ( ['foo', 'bar']
).
感谢您的帮助!
我的新数据框和旧列表:
My new dataframe and the old list:
abc = ['foo', 'bar']
df2 =
A B C
0 12 NaN 'bla'
1 23 NaN 'bla bla'
另一个数据框:
df3 =
A B C D
0 12 NaN 'bla' ['item1', 'item2']
1 23 NaN 'bla bla' [11, 12, 13]
我想将 'abc' 列表插入 df2.loc[1,'B']
和/或 df3.loc[1,'B']
.
I want insert the 'abc' list into df2.loc[1,'B']
and/or df3.loc[1,'B']
.
如果数据框的列仅包含整数值和/或 NaN 值和/或列表值,则将列表插入单元格可以完美地工作.如果数据框的列仅包含字符串值和/或 NaN 值和/或列表值,则将列表插入单元格可以完美地工作.但是,如果数据框包含具有整数和字符串值的列以及其他列,那么如果我使用它,则会出现错误消息: df2.loc[1,'B'] = abc
或 df3.loc[1,'B'] = abc
.
If the dataframe has columns only with integer values and/or NaN values and/or list values then inserting a list into a cell works perfectly. If the dataframe has columns only with string values and/or NaN values and/or list values then inserting a list into a cell works perfectly. But if the dataframe has columns with integer and string values and other columns then the error message appears if I use this: df2.loc[1,'B'] = abc
or df3.loc[1,'B'] = abc
.
另一个数据框:
df4 =
A B
0 'bla' NaN
1 'bla bla' NaN
这些插入工作完美:df.loc[1,'B'] = abc
或 df4.loc[1,'B'] = abc
..p>
These inserts work perfectly: df.loc[1,'B'] = abc
or df4.loc[1,'B'] = abc
.
df3.set_value(1, 'B', abc)
适用于任何数据帧.注意B"列的数据类型.例如.列表不能插入浮点列,在这种情况下 df['B'] = df['B'].astype(object)
可以提供帮助.
df3.set_value(1, 'B', abc)
works for any dataframe. Take care of the data type of column 'B'. Eg. a list can not be inserted into a float column, at that case df['B'] = df['B'].astype(object)
can help.
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