当时间大于 24 小时时,计算时间差的最佳方法是什么.
示例
$time1 = '76:00:00';$time2 = '30:00:00';//结果应该是 46:00:00echo date('H:i:s', strtotime($time1) - strtotime($time2));
但这不能用这个来完成,因为它大于 24 小时.
我还在数据库中存储了这样的时间:33:30:00我如何在 php 中将其格式化为:33:30
使用DateTime
和DateInterval
进行计算:
$date1 = new DateTime('now', new DateTimeZone('UTC'));$date2 = new DateTime('now', new DateTimeZone('UTC'));$time1 = new DateInterval('PT76H');$time2 = new DateInterval('PT30H');$date1->add($time1);$date2->add($time2);$diff = $date1->diff($date2);回声 ($diff->days * 24 + $diff->h) .$diff->format(':%I:%S');
说明:无法直接在 DateInterval
上执行计算,因此您必须创建日期作为计算的基础.然后将两个不同的间隔添加到当前日期,并计算它们之间的差异.diff()
返回包含总天数的 DateInterval
,您必须乘以 24 才能获得小时数,以及不等于完整天数的小时数.p>
时区应指定为 UTC 以避免夏令时问题.
What is the best way to calculate the difference in time, when time is greater than 24 hours.
Example
$time1 = '76:00:00';
$time2 = '30:00:00';
// result should be 46:00:00
echo date('H:i:s', strtotime($time1) - strtotime($time2));
But this could not be done with this because its greater then 24 hours.
Also in a database i've stored a time like this: 33:30:00 How in php could i format it to: 33:30
Use DateTime
and DateInterval
to perform calculations:
$date1 = new DateTime('now', new DateTimeZone('UTC'));
$date2 = new DateTime('now', new DateTimeZone('UTC'));
$time1 = new DateInterval('PT76H');
$time2 = new DateInterval('PT30H');
$date1->add($time1);
$date2->add($time2);
$diff = $date1->diff($date2);
echo ($diff->days * 24 + $diff->h) . $diff->format(':%I:%S');
Explanation:
It's not possible to perform calculations directly on DateInterval
s, so you have to create dates as a basis for calculations. Then add two different intervals to current dates, and calculate a difference between them. diff()
returns DateInterval
that contains total number of days, that you have to multiply by 24 to get hours, and hours that don't make full days.
EDIT: The timezone should be specified as UTC to avoid daylight saving time issues.
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