我正在用 Laravel Spark 1.0 (Laravel 5.2) 编写一个应用程序.我为代理(api)身份验证编写了一个自定义中间件.这是代码:
i'm writing an application in Laravel Spark 1.0 (Laravel 5.2). I wrote a custom middleware for agent (api) authentication. This is the code:
<?php
namespace AppHttpMiddleware;
use AppAgent;
use Closure;
use IlluminateHttpRequest;
class AgentAuth
{
/**
* Handle an incoming request.
*
* @param IlluminateHttpRequest $request
* @param Closure $next
* @return mixed
*/
public function handle($request, Closure $next)
{
if( isset($request->token) && !empty($request->token) )
{
$agent = Agent::where('token', '=', $request->token)->first();
if( $agent != NULL )
{
$team = $agent->Team()->first();
$user = $team->User()->first();
$request->merge(['team' => $team ]);
$request->merge(['user' => $user ]);
return $next($request);
}
else {
return response('Unauthorized 2.', 401);
}
}
else {
return response('Unauthorized 1.', 401);
}
}
}
在默认的 Laravel 身份验证中,用户对象被注入到请求中(参见 Laravel 文档):https://laravel.com/docs/5.2/authentication#retrieving-the-authenticated-user
In the default laravel authentication the user object is injected in the request (see laravel docs): https://laravel.com/docs/5.2/authentication#retrieving-the-authenticated-user
因此您可以使用以下方法检索用户:
So you can retrieve the user using:
$request->user();
Spark 显然是用这个方法来检查用户订阅是否有效(laravelsparksrcHttpMiddlewareVerifyUserIsSubscribed):
Spark obviously use this method to check if user subscription is valid (laravelsparksrcHttpMiddlewareVerifyUserIsSubscribed):
if ($this->subscribed($request->user(), $subscription, $plan, func_num_args() === 2)) {
return $next($request);
}
而且它不起作用,因为使用我的中间件,您可以使用以下方法检索用户:$request->user;
但不能使用 Laravel 默认值 $request->user();
And it's not working because, with my middleware, you can retrieve the user using: $request->user;
but not with the laravel defaults $request->user();
我应该如何将用户对象注入到请求中?
How should i inject the user object into the request?
提前致谢
服务提供者中的 Laravel (IlluminateAuthAuthServiceProvider@registerRequestRebindHandler)
Laravel in the service provider (IlluminateAuthAuthServiceProvider@registerRequestRebindHandler)
使用此代码将对象用户绑定到请求:
Use this code to bind object user to the request:
/**
* Register a resolver for the authenticated user.
*
* @return void
*/
protected function registerRequestRebindHandler()
{
$this->app->rebinding('request', function ($app, $request) {
$request->setUserResolver(function ($guard = null) use ($app) {
return call_user_func($app['auth']->userResolver(), $guard);
});
});
}
我尝试在中间件中插入此代码并进行适当的更正,但我不知道如何使其工作.
I tried to insert this code, with the appropriate correction, in the middleware but i can't figure out how to make it work.
我没有 Spark 的副本来尝试这个 &确保我所做的对你来说是正确的,但我认为这会有所帮助:
I don't have a copy of Spark to try this & ensure what I'm doing is correct for you, but I think this will help:
1) 一个假设 - 我相信你是说是的,这条线会让你找到你想要的用户:
1) An assumption - I believe you are saying that yes, this line will get you the user you want:
$user = $team->User()->first();
并且您只想将其绑定到请求,以便您稍后可以通过以下方式在您的应用中访问此用户:
and you merely want to bind it to the request so that you can access this user later in your app via:
$request->user()
2) 如果这是真的,那么我所做的就是简化您提供的代码以添加:
2) If this is true, then all I did was simplify the code you provided to add:
$request->merge(['user' => $user ]);
//add this
$request->setUserResolver(function () use ($user) {
return $user;
});
// if you dump() you can now see the $request has it
dump($request->user());
return $next($request);
我还在路由闭包中使用了 $request->user(),它就在那里.
I also $request->user() in the route closure, and it is there.
应用重新绑定对我来说有点奇怪,似乎没有必要.我不确定你正在做的事情是否真的需要这个.
The app rebinding was a little strange to me, and didn't seem necessary. I'm not sure that anything would really need this for what you are doing.
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