我目前正在编写两个类:HttpRequest 和 HttpResponse.我想编写自己的 HTTP 类.
I'm currently coding two classes: HttpRequest and HttpResponse. I want to code my own HTTP classes.
我在使用带有 enctype=multipart/form-data 的表单的 POST 方法时遇到问题:我无法获取请求内容.
I'm encountering an issue with a POST method using a form with enctype=multipart/form-data: I can't get the request contents.
经过长时间的研究和搜索，我发现我必须使用 file_get_contents("php://input") 来获取请求内容.当我测试它时，我有一个空字符串 var_dump(file_get_contents("php://input")).
After a long research and searchs, I've found I have to use file_get_contents("php://input") to get the request content.
When I test it, I have an empty string var_dump(file_get_contents("php://input")).
我无法访问服务器/php 配置.
I have no access to server/php configuration.
我正在使用以下代码进行测试:
I'm testing with the following code :
<?php
$input = file_get_contents('php://input');
var_dump($input);
?>
<html>
<body>
<form action="./" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="text" name="namen" id="nameid" /><br/>
<input type="file" name="file" id="file"><br>
<input type="file" name="file2" id="file2"><br>
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
提交后，我得到了这个结果:string(0) "".很明显，因为 php://input 不适用于 enctype="multipart/form-data" 表单.
And after submitting, I have this result : string(0) "".
It's obvious because php://input doesn't work with enctype="multipart/form-data" forms.
我想要类似的东西:
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="namen"
ds
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="file"; filename="toto.xml"
Content-Type: text/xml
<?xml version="1.0" encoding="UTF-8"?>
<Toto></Toto>
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="file2"; filename=""
Content-Type: application/octet-stream
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="submit"
Submit
-----------------------------19972703421793859182225487886--
它是否适用于任何请求方法?还是我错了?
Is a way it works for any request method ? Or am I wrong ?
我要在这里寻找一个显而易见的:为什么还要费心去尝试自己解析这个?数据在您的范围内，易于使用 $_POST[]/$_FILES[] ..
I'm going for the obvious one here: why even bother trying to parse this yourself? The data is within your range with the easy use of $_POST[] / $_FILES[] ..
您仍然可以围绕这些值构建您自己的类，而不是让您自己的类尝试完成与 php 编译器已经为您所做的相同的数据数组.
You can still build your own class around those values instead of having your own classes try to accomplish the same data array as the php-compiler already did for you.
为了给你一个有效的答案:我不知道有什么方法可以让你的 php://input 回来，因为它可能被 PHP 编译器读取，因此你在流的末尾(另外:它是只读的，因此可能无法将指针重置为流的开头).
In order to give you a valid answer: I don't know of a way to get your php://input back, as it is probably read by the PHP compiler and therefore you are at the end of the stream ( plus: it is read-only so there is probably no way to reset the pointer to the start of the stream ).
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