我正在尝试获取包含文件夹和子文件夹的列表我有以下内容可以让我获取文件夹和子文件夹但我需要像下面这样整理它我一直在尝试但我不知道如何我会绕过.
I am trying to get a list with folders and sub folders i have the following that allows me to get the folders and sub folders but i needed it to be sorted out like the e.g below i have been trying but i dont know how i would get around.
Root/
Root/Images
Root/Images/UserImages
Root/Text/
Root/Text/User1/
Root/Text/User1/Folder2
但是在monent它的显示是这样的
but at the monent its display like this
Root/css/
tree/css/
js/
images/
PHP 代码:
function ListFolder($path)
{
$dir_handle = @opendir($path) or die("Unable to open $path");
//Leave only the lastest folder name
$dirname = end(explode("/", $path));
//display the target folder.
echo ("$dirname/");
while (false !== ($file = readdir($dir_handle)))
{
if($file!="." && $file!="..")
{
if (is_dir($path."/".$file))
{
//Display a list of sub folders.
ListFolder($path."/".$file);
echo "<br>";
}
}
}
//closing the directory
closedir($dir_handle);
}
ListFolder("../");
谢谢
将目录名收集到一个数组中,而不是直接echo
.在数组上使用 sort
和 foreach
循环来打印列表.
Collect the directory names in an array instead of echo
ing them directly. Use sort
on the array and a foreach
-loop to print the list.
所以代替 echo ("$dirname/");
你会使用 $dirnames[] = $dirname;
(使 $dirnames 全局并在你之前初始化它第一次调用ListFolder").然后在递归运行ListFolder"之后,您将执行 sort($dirnames);
然后像这样的输出:
So instead of echo ("$dirname/");
you would use $dirnames[] = $dirname;
(make $dirnames global and initialize it before your first call of "ListFolder"). Then after the recursive run of "ListFolder", you'd execute sort($dirnames);
and then something like this for the output:
foreach ($dirnames as $dirname)
{
echo $dirname . '<br />';
}
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