我正在使用这段代码:
$target = 'extracted/' .$名称[0];$scan = scandir($target);
扫描用于 zip 上传的文件夹的目录.我希望能够在我的 $target
文件夹中找到所有文件夹,以便我可以删除它们及其内容,只留下 $target
目录中的文件.
一旦我返回了文件夹的内容,我不知道如何区分文件夹和文件才能删除文件夹.
另外,我被告知 rmdir()
函数无法删除其中包含内容的文件夹,有什么办法可以解决这个问题吗?
谢谢,本.
使用is_dir()
和 is_file()
函数确定你是否有文件夹或文件代码>
例如:
<前>$path = '提取/' .$名称[0];$results = scandir($path);foreach ($results as $result) {if ($result === '.' or $result === '..') continue;if (is_dir($path . '/' . $result)) {//如果目录使用的代码}}I am using this peice of code:
$target = 'extracted/' . $name[0];
$scan = scandir($target);
To scan the directory of a folder which is used for zip uploads. I want to be able to find all the folders inside my $target
folder so I can delete them and their contents, leaving only the files in the $target
directory.
Once I have returned the contents of the folder, I don't know how to differentiate between the folders and the files to be able to delete the folders.
Also, I have been told that the rmdir()
function can't delete folders which have content inside them, is there any way around this?
Thanks, Ben.
To determine whether or not you have a folder or file use the functions is_dir()
and is_file()
For example:
$path = 'extracted/' . $name[0]; $results = scandir($path); foreach ($results as $result) { if ($result === '.' or $result === '..') continue; if (is_dir($path . '/' . $result)) { //code to use if directory } }
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