我正在尝试使用 MySQl 准备好的语句从数据库中获取行并获得结果.然而,这是行不通的.
请有人知道我哪里出错了吗?我已经尝试了几个小时的解决方案,但我无法让它发挥作用.该页面不会加载,就好像查询失败一样.
$tag = trim($_GET['tag']);$stmt = $mysqli->prepare('SELECT posts.* FROM tags JOIN posts ON posts.id = tags.post_id WHERE tag = ?');$stmt->bind_param('s', $tag);$stmt->execute();$stmt->store_result();$result = $stmt->get_result();while ($row = $result->fetch_assoc()) {回声 $row['tag'];}$stmt->free_result();$stmt->close();
试试这个:
$stmt = $mysqli->prepare('SELECT posts.id FROM tags JOIN posts ON posts.id = tags.post_id WHERE tag = ?');...$stmt->bind_result($id);而 ($stmt-> fetch()) {//var_dump 整行以确保您期望的密钥可用var_dump($id);}
更新
如果你想做一个选择 *,而不是单独指定每一列,看看这个 post(不是接受的答案,而是得分最高的答案).否则,我强烈建议您查看 PDO,因为它使这些基本的读取操作变得更加容易.>
I am trying to get rows from the database using MySQl prepared statements and get result. However this is not working.
Please can someone see where I am going wrong? I have been trying solutions for hours but I can't get it to work. The page just doesn't load as if the query has failed.
$tag = trim($_GET['tag']);
$stmt = $mysqli->prepare('SELECT posts.* FROM tags JOIN posts ON posts.id = tags.post_id WHERE tag = ?');
$stmt->bind_param('s', $tag);
$stmt->execute();
$stmt->store_result();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
echo $row['tag'];
}
$stmt->free_result();
$stmt->close();
Try this:
$stmt = $mysqli->prepare('SELECT posts.id FROM tags JOIN posts ON posts.id = tags.post_id WHERE tag = ?');
...
$stmt->bind_result($id);
while ($stmt->fetch()) {
// var_dump entire row to ensure the key you expect is avail
var_dump($id);
}
Upate
If you want to do a select *, vs having to specify EVERY column individually, check out this post (not the accepted answer, but the highest scoring answer). Otherwise I strongly urge you to check out PDO, as it makes these basic read ops much easier.
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