我试图在获取数据库结果的同时在 while 循环中使用 json_encode()
.这是我的代码:
I am trying to use json_encode()
in a while loop while getting database results. Here is my code:
<?
$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);
$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");
while($row = sqlite_fetch_array($results)) {
$data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));
sqlite_close($database);
?>
这个输出是
{"response":"lastUserID lastUser lastXPos lastYPos"}
{"response":"lastUserID lastUser lastXPos lastYPos"}
我希望它是...
{"response":["1 Alex 10 12", "2 Fred 27 59", "3 Tom 47 19"]}
{"response":["1 Alex 10 12", "2 Fred 27 59", "3 Tom 47 19"]}
等
所以我希望 json_encode()
函数将所有用户放入数组而不是最后一个.我该怎么做?谢谢
So I want the json_encode()
function to put ALL users into the array rather than the last one. How would I do this? Thanks
尝试:
<?
$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);
$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");
$data = array();
while($row = sqlite_fetch_array($results)) {
$data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));
sqlite_close($database);
?>
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