我正在尝试在春季将列表转换为页面.我已经使用
I am trying to convert list to page in spring. I have converted it using
new PageImpl(users, pageable, users.size());
new PageImpl(users, pageable, users.size());
但现在我遇到了排序和分页本身的问题.当我尝试传递大小和页面时,分页不起作用.
But now I having problem with sorting and pagination itself. When I try passing size and page, the pagination doesn't work.
这是我正在使用的代码.
Here's the code I am using.
我的控制器
public ResponseEntity<User> getUsersByProgramId(
@RequestParam(name = "programId", required = true) Integer programId Pageable pageable) {
List<User> users = userService.findAllByProgramId(programId);
Page<User> pages = new PageImpl<User>(users, pageable, users.size());
return new ResponseEntity<>(pages, HttpStatus.OK);
}
这是我的用户回购
public interface UserRepo extends JpaRepository<User, Integer>{
public List<User> findAllByProgramId(Integer programId);
这是我的服务
public List<User> findAllByProgramId(Integer programId);
我也遇到了同样的问题.我使用了子列表:
I had the same problem. I used subList:
final int start = (int)pageable.getOffset();
final int end = Math.min((start + pageable.getPageSize()), users.size());
final Page<User> page = new PageImpl<>(users.subList(start, end), pageable, users.size());
这篇关于Spring中List到Page的转换的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!