如何以相反的顺序获取 char 数组?

时间:2023-04-05
本文介绍了如何以相反的顺序获取 char 数组?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我的作业题是这样的

编写一个程序,以相反的顺序打印字符数组中的字母

Write a program which prints the letters in a char array in reverse order using

void printReverse(char letters[], int size);

例如,如果数组包含 {'c', 's', 'c', '2', '6', '1'},则输出应为162csc".

For example, if the array contains {'c', 's', 'c', '2', '6', '1'} the output should be "162csc".

试过了,不知道什么意思

I tried, but I don't know what it means

void printReverse(char letters[], int size);

我这样做了,但调用方法printReverse"时出现问题.进入main方法

I did this but there's a problem with calling the method "printReverse" into the main method

import java.util.Arrays;
import java.util.Collections;
 
public class search {

    public static void main(String[] args) {          
 
        char[] letters = {'e', 'v', 'o', 'l', '4'};
        printReverse();

    }

    public void printReverse(char[] letters, int size) {
    
        for (int i = letters.length-1; i >= 0 ; i--) {
        System.out.print(letters[i]);
    }
}

推荐答案

我相信你写的就是你必须创建的方法的签名.

I believe what you wrote is the signature of the method you have to create.

public void printReverse(char[] letters, int size){
   //code here
}

您必须迭代数组并向后打印它包含的内容.使用反向for 循环"遍历字母"中的每个项目.我会让你自己把这些结合起来,因为这是一项任务.下面是一个 for 循环的例子:

You would have to iterate the array and print what it contains backwards. Use a reverse "for loop" to go through each item in "letters". I'll let you combine these yourself as it's an assignment. Here's an example of a for loop:

for (int i = array.length-1; i >= 0 ; i--){
    System.out.print(array[i]);
}

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