如何使用 Java 和 SAX 解析我的简单 XML 文件?

问题描述

我正在尝试解析下面的文件.我想打印每位乘客的身份证和姓名.能给我代码解析一下吗?

I am trying to parse the file below. I want to print the id and name of each passenger. Can you give me code to parse it ?

<?xml version="1.0" encoding="utf-8"?>
<root xmlns:android="www.google.com">

<passenger id = "001">
<name>Tom Cruise</name>
</passenger>

<passenger id = "002">
<name>Tom Hanks</name>
</passenger>

</root>

更新这是我尝试过的.这里提到的代码、问题等 -简单 SAX 解析器输出错误

UPDATE This is what i had tried. Code, problems etc mentioned here - Error in output of a simple SAX parser

推荐答案

下面是一个工作示例，虽然我建议你改用 StAX，但你会发现 SAX 不是很方便

Here is a working example to start with, though I suggest you to use StAX instead, you will see that SAX is not very convenient

import java.io.File;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class SAX2 {

    public static void main(String[] args) throws Exception {
        SAXParser parser = SAXParserFactory.newInstance().newSAXParser();
        parser.parse(new File("test.xml"), new DefaultHandler() {

            @Override
            public void startElement(String uri, String localName,
                    String qName, Attributes atts) throws SAXException {
                if (qName.equals("passenger")) {
                    System.out.println("id = " + atts.getValue(0));
                }
            }

            @Override
            public void endElement(String uri, String localName, String qName)
                    throws SAXException {
            }

            @Override
            public void characters(char[] ch, int start, int length)
                    throws SAXException {
                String text = new String(ch, start, length);
                if (!text.trim().isEmpty()) {
                    System.out.println("name " + text);
                }
            }
        });
    }
}

输出

id = 001
name Tom Cruise
id = 002
name Tom Hanks

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