我有以下数据集
Account Contact
1 324324324
1 674323234
2 833343432
2 433243443
3 787655455
4 754327545
4 455435435
5 543544355
5 432455553
5 432433242
5 432432432
我希望输出如下:
Account Contact1 Contact2 Contact3 Contact4
1 324324324 674323234
2 833343432 433243443
3 787655455
4 754327545 455435435
5 543544355 432455553 432433242 432432432
问题还在于我有一个不固定数量的 Accounts &不固定数量的联系人
The problem is also that I have an unfixed amount of Accounts & unfixed amount of Contacts
如果您要应用 PIVOT
函数,您将需要使用聚合函数来获得结果,但您也将想使用像 row_number()
这样的窗口函数来为帐户中的每个联系人生成唯一的序列.
If you are going to apply the PIVOT
function, you will need to use an aggregate function to get the result but you will also want to use a windowing function like row_number()
to generate a unique sequence for each contact in the account.
首先,您将查询类似于以下内容的数据:
First, you will query your data similar to:
select account, contact,
'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
参见SQL Fiddle with Demo.这将创建一个具有唯一序列的新列:
See SQL Fiddle with Demo. This will create a new column with the unique sequence:
| ACCOUNT | CONTACT | SEQ |
|---------|-----------|----------|
| 1 | 324324324 | contact1 |
| 1 | 674323234 | contact2 |
如果您的列数有限,那么您可以对查询进行硬编码:
If you have a limited number of columns, then you could hard-code your query:
select account,
contact1, contact2, contact3, contact4
from
(
select account, contact,
'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) d
pivot
(
max(contact)
for seq in (contact1, contact2, contact3, contact4)
) piv;
参见SQL Fiddle with Demo
如果您有未知数量的列,那么您将不得不使用动态 SQL:
If you have an unknown number of columns, then you will have to use dynamic SQL:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(seq)
from
(
select 'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) d
group by seq
order by seq
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT account, ' + @cols + '
from
(
select account, contact,
''contact''
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) x
pivot
(
max(contact)
for seq in (' + @cols + ')
) p '
execute sp_executesql @query;
参见SQL Fiddle with Demo.两者都会给你一个结果:
See SQL Fiddle with Demo. Both will give you a result of:
| ACCOUNT | CONTACT1 | CONTACT2 | CONTACT3 | CONTACT4 |
|---------|-----------|-----------|-----------|-----------|
| 1 | 324324324 | 674323234 | (null) | (null) |
| 2 | 433243443 | 833343432 | (null) | (null) |
| 3 | 787655455 | (null) | (null) | (null) |
| 4 | 455435435 | 754327545 | (null) | (null) |
| 5 | 432432432 | 432433242 | 432455553 | 543544355 |
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