在Oracle中,如果我有一个表定义为……
In Oracle, if I have a table defined as …
CREATE TABLE taxonomy
(
key NUMBER(11) NOT NULL CONSTRAINT taxPkey PRIMARY KEY,
value VARCHAR2(255),
taxHier NUMBER(11)
);
ALTER TABLE
taxonomy
ADD CONSTRAINT
taxTaxFkey
FOREIGN KEY
(taxHier)
REFERENCES
tax(key);
有了这些值......
With these values …
key value taxHier
0 zero null
1 one 0
2 two 0
3 three 0
4 four 1
5 five 2
6 six 2
这个查询语法……
SELECT
value
FROM
taxonomy
CONNECT BY
PRIOR key = taxHier
START WITH
key = 0;
会产生……
zero
one
four
two
five
six
three
这在 PostgreSQL 中是如何完成的?
How is this done in PostgreSQL?
在 Postgres 中使用 RECURSIVE CTE
:
Use a RECURSIVE CTE
in Postgres:
WITH RECURSIVE cte AS (
SELECT key, value, 1 AS level
FROM taxonomy
WHERE key = 0
UNION ALL
SELECT t.key, t.value, c.level + 1
FROM cte c
JOIN taxonomy t ON t.taxHier = c.key
)
SELECT value
FROM cte
ORDER BY level;
我之前回答中的详细信息和文档链接:
Details and links to documentation in my previous answer:
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