我想将以下字符串转换为日期:
I want to convert the follow string to date:
2004-09-30 23:53:48,140000000
我试过了:
to_date('#', 'YYYY-MM-DD HH24:MI:SS,FF9')
但是 PL/SQL 不断抛出这个错误:
But PL/SQL keep throwing this error:
ORA-01821: date format not recognized.
FF9 对 Oracle 不正确,有什么建议吗?
FF9 is incorrect for Oracle, any suggestion?
Oracle
仅在 DATE
字段中存储最高达秒的分数.
Oracle
stores only the fractions up to second in a DATE
field.
改用TIMESTAMP
:
SELECT TO_TIMESTAMP('2004-09-30 23:53:48,140000000', 'YYYY-MM-DD HH24:MI:SS,FF9')
FROM dual
,可能将其转换为 DATE
然后:
, possibly casting it to a DATE
then:
SELECT CAST(TO_TIMESTAMP('2004-09-30 23:53:48,140000000', 'YYYY-MM-DD HH24:MI:SS,FF9') AS DATE)
FROM dual
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