我有这个超长的 SQL 查询,现在这个查询执行以下操作,创建第一个级别,即 Job_No....第二个级别中的下一个获取所有BaselineStart",但是这将每个 BaselineStart 与 baseOrSchedStartList 分开,我想要做的是为每个 Job_No 设置 1 个 baseOrSchedStartList,并在 baseOrSchedStartList 下设置每个字符串".我希望这是有道理的.这是我的查询:
I have this super long SQL query, now what this query does is the following, creates the first level which is the Job_No....next in the second level gets all the 'BaselineStart' however this separates each BaselineStart with baseOrSchedStartList, what I am looking to do is have 1 baseOrSchedStartList for each Job_No and have each 'string' under baseOrSchedStartList. I hope this makes sense. Here is my query:
SELECT [Job_No] as '@Key',
(
SELECT ISNULL(UserDate1,ScheduleTasks.BaselineStart) AS 'string'
FROM ScheduleTasks INNER JOIN Schedule ON ScheduleTasks.ScheduleID = Schedule.ScheduleID INNER JOIN V_CONSTAT_ACTUAL_DATES ON V_CONSTAT_ACTUAL_DATES.JOB_NUMBER = Schedule.Job_No WHERE Job_No IN (SELECT JOB_NUMBER
FROM V_CONSTAT_ACTUAL_DATES
WHERE AREA_DESC = 'Orchard Park'
AND (DATE_TO_END IS NOT NULL AND DATE_TO_END >= GETDATE())) AND
(
LibraryTaskID <> 203
AND LibraryTaskID <> 204
AND LibraryTaskID <> 210
AND LibraryTaskID <> 211
AND LibraryTaskID <> 214
AND LibraryTaskID <> 215
AND LibraryTaskID <> 218
AND LibraryTaskID <> 219
AND LibraryTaskID <> 224
AND LibraryTaskID <> 227
AND LibraryTaskID <> 230
AND LibraryTaskID <> 231
AND LibraryTaskID <> 232
AND LibraryTaskID <> 233
AND LibraryTaskID <> 234
AND LibraryTaskID <> 235
AND LibraryTaskID <> 236
AND LibraryTaskID <> 237
AND LibraryTaskID <> 238
AND LibraryTaskID <> 239
AND LibraryTaskID <> 240
AND LibraryTaskID <> 242
AND LibraryTaskID <> 243
AND LibraryTaskID <> 295
AND LibraryTaskID <> 299
AND LibraryTaskID <> 303
AND LibraryTaskID <> 304
AND LibraryTaskID <> 305
AND LibraryTaskID <> 313
AND LibraryTaskID <> 314
AND LibraryTaskID <> 321
AND LibraryTaskID <> 333
)
ORDER BY DATE_TO_END, SortOrder
FOR XML PATH('baseOrSchedStartList'), Type
)
FROM ScheduleTasks INNER JOIN Schedule ON ScheduleTasks.ScheduleID = Schedule.ScheduleID INNER JOIN V_CONSTAT_ACTUAL_DATES ON V_CONSTAT_ACTUAL_DATES.JOB_NUMBER = Schedule.Job_No WHERE Job_No IN (SELECT JOB_NUMBER
FROM V_CONSTAT_ACTUAL_DATES
WHERE AREA_DESC = 'Orchard Park'
AND (DATE_TO_END IS NOT NULL AND DATE_TO_END >= GETDATE())) AND
(
LibraryTaskID <> 203
AND LibraryTaskID <> 204
AND LibraryTaskID <> 210
AND LibraryTaskID <> 211
AND LibraryTaskID <> 214
AND LibraryTaskID <> 215
AND LibraryTaskID <> 218
AND LibraryTaskID <> 219
AND LibraryTaskID <> 224
AND LibraryTaskID <> 227
AND LibraryTaskID <> 230
AND LibraryTaskID <> 231
AND LibraryTaskID <> 232
AND LibraryTaskID <> 233
AND LibraryTaskID <> 234
AND LibraryTaskID <> 235
AND LibraryTaskID <> 236
AND LibraryTaskID <> 237
AND LibraryTaskID <> 238
AND LibraryTaskID <> 239
AND LibraryTaskID <> 240
AND LibraryTaskID <> 242
AND LibraryTaskID <> 243
AND LibraryTaskID <> 295
AND LibraryTaskID <> 299
AND LibraryTaskID <> 303
AND LibraryTaskID <> 304
AND LibraryTaskID <> 305
AND LibraryTaskID <> 313
AND LibraryTaskID <> 314
AND LibraryTaskID <> 321
AND LibraryTaskID <> 333
)
GROUP BY [Job_No]
FOR XML PATH('Job_No'), ROOT('Root')
此查询返回此数据:
<Root>
<Job_No Key="ORC0023">
<baseOrSchedStartList>
<string>2015-09-11T08:00:00</string>
</baseOrSchedStartList>
<baseOrSchedStartList>
<string>2015-08-10T16:00:00</string>
</baseOrSchedStartList>
<baseOrSchedStartList>
<string>2015-08-11T16:00:00</string>
</baseOrSchedStartList>
</Job_No>
</Root>
我正在寻找的是以下内容:
what I am looking for is the following:
<Root>
<Job_No Key="ORC0023">
<baseOrSchedStartList>
<string>2015-09-11T08:00:00</string>
<string>2015-08-10T16:00:00</string>
<string>2015-08-11T16:00:00</string>
</baseOrSchedStartList>
</Job_No>
</Root>
任何帮助将不胜感激.
如果你从 AS [@Key]
中去掉 @
你会得到这个
If you just take away the @
from the AS [@Key]
you'll get this
DECLARE @tbl TABLE([Key] VARCHAR(10),DateValue DATETIME);
INSERT INTO @tbl VALUES ('ORC0023','2015-09-11T08:00:00')
,('ORC0023','2015-08-10T16:00:00')
,('ORC0023','2015-08-11T16:00:00')
DECLARE @UniqueKey VARCHAR(10)='ORC0023';
SELECT @UniqueKey AS [Key]
,(
SELECT DateValue AS [string]
FROM @tbl AS tbl
WHERE tbl.[Key]=@UniqueKey
FOR XML PATH(''),TYPE
) AS baseOrSchedStartList
FOR XML PATH('Job_No'),ROOT('Root')
/*
<Root>
<Job_No>
<Key>ORC0023</Key>
<baseOrSchedStartList>
<string>2015-09-11T08:00:00</string>
<string>2015-08-10T16:00:00</string>
<string>2015-08-11T16:00:00</string>
</baseOrSchedStartList>
</Job_No>
</Root>
*/
尝试将 as '@Key'
更改为 as Key
和
ORDER BY DATE_TO_END, SortOrder
FOR XML PATH('baseOrSchedStartList'), Type
)
到
ORDER BY DATE_TO_END, SortOrder
FOR XML PATH(''), Type
) AS baseOrSchedStartList
另一种选择 - 正如 BateTech 在评论中指出的 - 将您的baseOrSchedStart"作为 ,ROOT('baseOrSchedStart')
放在 FOR XML PATH('')
并让括号未命名...
Another alternative was - as pointed out by BateTech in a comment - to put your "baseOrSchedStart" as ,ROOT('baseOrSchedStart')
behind the FOR XML PATH('')
and let the paranthesis unnamed...
如果没有您的表结构和测试数据,就很难完全理解您的查询(实际上不是超长 :-))
Without your table's structures and test data it is difficult to fully understand your query (which isn't that super long actually :-) )
因此我准备了一个简化的结构示例,希望您能理解该方法并将其转移到您的实际数据中
Therefore I prepared a simplified structure example and hope, that you can understand the approach and transfer this to your actual data
请尝试以下操作:
DECLARE @tbl TABLE([Key] VARCHAR(10),DateValue DATETIME);
INSERT INTO @tbl VALUES ('ORC0023','2015-09-11T08:00:00')
,('ORC0023','2015-08-10T16:00:00')
,('ORC0023','2015-08-11T16:00:00')
DECLARE @UniqueKey VARCHAR(10)='ORC0023';
--This is structurally what you've got
SELECT @UniqueKey AS [@Key]
,(
SELECT DateValue AS [string]
FROM @tbl AS tbl
WHERE tbl.[Key]=@UniqueKey
FOR XML PATH('baseOrSchedStartList'),TYPE
)
FOR XML PATH('Job_No'),ROOT('Root')
/*
<Root>
<Job_No Key="ORC0023">
<baseOrSchedStartList>
<string>2015-09-11T08:00:00</string>
</baseOrSchedStartList>
<baseOrSchedStartList>
<string>2015-08-10T16:00:00</string>
</baseOrSchedStartList>
<baseOrSchedStartList>
<string>2015-08-11T16:00:00</string>
</baseOrSchedStartList>
</Job_No>
</Root>
*/
现在试试这个
SELECT @UniqueKey AS [@Key]
,(
SELECT DateValue AS [*]
FROM @tbl AS tbl
WHERE tbl.[Key]=@UniqueKey
FOR XML PATH('string'),TYPE
) AS baseOrSchedStartList
FOR XML PATH('Job_No'),ROOT('Root')
/*
<Root>
<Job_No Key="ORC0023">
<baseOrSchedStartList>
<string>2015-09-11T08:00:00</string>
<string>2015-08-10T16:00:00</string>
<string>2015-08-11T16:00:00</string>
</baseOrSchedStartList>
</Job_No>
</Root>
*/
顺便说一句:这和这个一样:
Btw: This is the same as this:
SELECT @UniqueKey AS [@Key]
,(
SELECT DateValue AS [string]
FROM @tbl AS tbl
WHERE tbl.[Key]=@UniqueKey
FOR XML PATH(''),TYPE
) AS baseOrSchedStartList
FOR XML PATH('Job_No'),ROOT('Root')
这篇关于嵌套行的 SQL FOR XML 列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!