Active Directory 用户组成员资格 GroupPrincipal

时间:2022-11-27
本文介绍了Active Directory 用户组成员资格 GroupPrincipal的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我正在尝试使用 GroupPrincipal(System.DirectoryServices.AccountManagement 命名空间的一部分)来填充类型字符串的列表,因此我可以检查是否用户是 Active Directory 组的成员.这是我迄今为止编写的编辑类:

I am trying to use GroupPrincipal (part of the System.DirectoryServices.AccountManagement namespace) to populate a list of type string, so I can check to see if a user is a member of an Active Directory group. Here is the edited class that I have written so far:

public class ActiveDirectoryMembership
{
    private PrincipalContext context = new PrincipalContext(ContextType.Domain, Environment.UserDomainName);
    private List<string> GroupName {get;set;}

    public ActiveDirectoryMembership() 
    {
         //Code snipped - this part returns a list of users
         populateGroups();
    }

    private void populateGroups()
    {
        GroupPrincipal SearchGroup = GroupPrincipal.FindByIdentity(context, "Group Name");
        GroupName = new List<string>();
        foreach (UserPrincipal p in GroupName.GetMembers())
        {
           GroupName.add(p.SamAccountName);
        }
    }

那么,我哪里出错了?

提前致谢:)

推荐答案

此代码修改有效(我进行了测试以确保):

This modification of your code works (I made tests to ensure):

using System.DirectoryServices.AccountManagement;


    private static readonly string DomainName = "domaincontrollercomputer.domain.com";
    private static readonly string DomainContainer = "DC=DOMAIN,DC=COM";
    private static readonly string ADGroupName = "AD Group Name";
    private List<string> GroupName {get;set;}
      
    private void populateGroups()
    {
        using (var ctx = new PrincipalContext(ContextType.Domain, DomainName, DomainContainer))
        {
            using (var grp = GroupPrincipal.FindByIdentity(ctx, ADGroupName))
            {
                GroupName = new List<string>();
                foreach (var member in grp.GetMembers())
                {
                    GroupName.Add(member.SamAccountName);
                }
            }
        }
    }

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