有什么方法吗?我的电脑是AMD64.
Is there any method? My computer is AMD64.
::std::string str;
BOOL loadU(const wchar_t* lpszPathName, int flag = 0);
当我使用:
loadU(&str);
VS2005 编译器说:
the VS2005 compiler says:
Error 7 error C2664:: cannot convert parameter 1 from 'std::string *__w64 ' to 'const wchar_t *'
我该怎么做?
如果你有一个 std::wstring 对象，你可以在它上面调用 c_str() 来得到一个 wchar_t*:
If you have a std::wstring object, you can call c_str() on it to get a wchar_t*:
std::wstring name( L"Steve Nash" );
const wchar_t* szName = name.c_str();
然而，由于您在一个狭窄的字符串上操作，您首先需要将其加宽.这里有多种选择；一种是使用Windows内置的MultiByteToWideChar 例程.这会给你一个 LPWSTR，它等价于 wchar_t*.
Since you are operating on a narrow string, however, you would first need to widen it. There are various options here; one is to use Windows' built-in MultiByteToWideChar routine. That will give you an LPWSTR, which is equivalent to wchar_t*.
这篇关于我想将 std::string 转换为 const wchar_t *的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！