只是出于好奇:如果我有嵌套的作用域,就像在这个示例 C++ 代码中一样
Just out of curiosity: if I have nested scopes, like in this sample C++ code
using namespace std;
int v = 1; // global
int main (void)
{
int v = 2; // local
{
int v = 3; // within subscope
cout << "subscope: " << v << endl;
// cout << "local: " << v << endl;
cout << "global: " << ::v << endl;
}
cout << "local: " << v << endl;
cout << "global: " << ::v << endl;
}
有没有办法从中间"范围(非全局或本地)访问变量 v
的值 2
?
Is there any way to access the variable v
with the value 2
from the "intermediate" scope (neither global nor local)?
你可以像这样声明一个新的引用作为别名
You can declare a new reference as an alias like so
int main (void)
{
int v = 2; // local
int &vlocal = v;
{
int v = 3; // within subscope
cout << "local: " << vlocal << endl;
}
}
但我会完全避免这种做法.我花了几个小时来调试这样的构造,因为在调试器中显示的变量因范围而改变,我无法弄清楚它是如何改变的.
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