来自我继承的类的构造函数需要传入一个非平凡的对象.类似于:
A constructor from a class I'm inheriting requires a non-trivial object to be passed in. Similar to this:
MyFoo::MyFoo() : SomeBase( complexstuff )
{
return;
}
complexstuff 与 MyFoo 关系不大，所以我不想传入.
The complexstuff has little to do with MyFoo, so I didn't want to have to pass it in.
我没有编写某种返回 complexstuff 的 1-off 临时函数，而是使用了 lambda.我花了几分钟才弄清楚我必须调用 lambda.所以我的代码现在看起来像这样:
Instead of writing some kind of 1-off temporary function that returns complexstuff I used a lambda. What took me a few minutes to figure out is I have to invoke the lambda. So my code now looks like this:
MyFoo::MyFoo() : SomeBase(
[]()
{
/* blah blah do stuff with complexstuff */
return complexstuff;
} () )
{
return;
}
如果你没有抓住它，那就是微妙的.但是在 lambda 主体之后，我不得不放置 () 来告诉编译器立即运行"lambda.在我弄清楚我做错了什么之后，这是有道理的.否则，如果没有 () 来调用 lambda，gcc 会说类似这样的话:
If you didn't catch it, it is subtle. But after the lambda body, I had to put () to tell the compiler to immediately "run" the lambda. Which made sense after I figured out what I had done wrong. Otherwise, without the () to invoke the lambda, gcc says something similar to this:
error: no matching function for call to 'SomeBase(<lambda()>)'
但现在我在想——我做对了吗?在 C++11 或 C++14 中是否有更好的方法来告诉编译器我希望它立即调用我编写的 lambda?还是像我通常的做法那样附加一个空的 () ?
But now that has me thinking -- did I do this correctly? Is there a better way in C++11 or C++14 to tell the compiler that I want it to immediately invoke a lambda I've written? Or is appending an empty () like I did the usual way to do this?
但现在我在想——我做对了吗?
But now that has me thinking -- did I do this correctly?
是的，你做到了.
在 C++11 或 C++14 中是否有更好的方法来告诉编译器我希望它立即调用我编写的 lambda?
Is there a better way in C++11 or C++14 to tell the compiler that I want it to immediately invoke a lambda I've written?
我不知道.一个 lambda 也只是一个函数对象，所以你需要有一个 () 来调用它，没有办法绕过它(当然除了一些调用lambda 就像 std::invoke).
Not that I know of. A lambda is also just a function object, so you need to have a () to call it, there is no way around it (except of course some function that invokes the lambda like std::invoke).
如果您愿意，可以在捕获列表之后删除 ()，因为您的 lambda 不带任何参数.
If you want you can drop the () after the capture list, because your lambda doesn't take any parameters.
还是像我通常的做法那样附加一个空的 () ?
Or is appending an empty
()like I did the usual way to do this?
是的，这是最短的路.如前所述，std::invoke 也可以替代，但它需要更多的输入.我会说使用 () 直接调用是通常的做法.
Yes, it is the shortest way. As said before, std::invoke would also work instead, but it requires more typing. I would say a direct call with () is the usual way it is done.
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