问题描述
这是我用于创建和渲染包含具有顶点位置的 VBO 的 VAO 的代码.但不幸的是它不起作用.它绘制一个三角形而不是一个四边形.但是当我把loadToVAO函数的代码放在while循环之前的update函数中时,它就起作用了.
This is my code for creating and rendering a VAO that contains a VBO with the vertex positions. But unfortunately it doesn't work. It draws a triangle instead of a quad. But when I put the code of the loadToVAO function in the update function before the while loop, it works.
推荐答案
sizeof
运算符始终返回基础类型的大小.当你把loadToVAO
的内容复制到update函数中时,sizeof(vertices)
基本上就是sizeof(float[18])
,也就是数组的总大小.
The sizeof
operator always returns the size of the underlying type. When you copy the content of loadToVAO
to the update function, sizeof(vertices)
is basically sizeof(float[18])
, which is the total size of the array.
但是在 loadToVAO
中,sizeof(vertices)
将函数参数 vertices
作为输入而不是全局变量.由于在 C++ 中未定义大小的数组参数被视为我们这里的相同类型的点:
But inside the loadToVAO
, the sizeof(vertices)
takes the function parameter vertices
as input and not the global variable. Since array parameters of undefined size in C++ are treated as points of the same type we have here:
它是指针的大小(4 或 8),不再是数据的大小.
which is the size of a pointer (4 or 8) and not the size of the data anymore.
要解决这个问题,您可以将数组的大小也传递给函数,这是 C 的方法.更现代的方法是首先使用 std::array
或 std::vector
来存储数据.
To solve this, you can either pass the size of the array also to the function, which is the C way to go. The more modern way is to use std::array
or std::vector
to store the data in the first place.
第二次查看时,我看到您首先使用了 sizeof(vertices) * 8
.我不太确定 8 是从哪里来的,因为你既没有 8 个元素,浮点数也没有 8 个字节的大小.
On the second look I saw that you used sizeof(vertices) * 8
in the first place. I'm not really sure where the 8 comes from, since you neither have 8 elements nor does a float have a size of 8 bytes.
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