dedecms5.7sp1评论添加字段的解决方法问题

alter table dede_feedback add column website varchar(20);

按确定执行即可。如果显示“执行一个命令”就说明添加成功了。

2，打开:feedback_ajax.php，找到：

include_once(DEDEINC.'/memberlogin.class.php');
$cfg_ml = new MemberLogin(

$website = cn_substrR($website,50);

$inquery = "INSERT INTO `cn_feedback`(`aid`,`typeid`,`username`,`arctitle`,`ip`,`ischeck`,`dtime`, `mid`,`bad`,`good`,`ftype`,`face`,`msg`)
VALUES ('$aid','$typeid','$username','$arctitle','$ip','$ischeck','$dtime', '{$cfg_ml->M_ID}','0','0','$feedbacktype','$face','$msg'); ";

$inquery = "INSERT INTO `cn_feedback`(`aid`,`typeid`,`username`,`arctitle`,`ip`,`ischeck`,`dtime`, `mid`,`bad`,`good`,`ftype`,`face`,`msg`,`website`)
VALUES ('$aid','$typeid','$username','$arctitle','$ip','$ischeck','$dtime', '{$cfg_ml->M_ID}','0','0','$feedbacktype','$face','$msg','$website'); ";

<label for="url">Website</label><input id="url" name="website" value="" size="30" type="text">

找到

myajax.AddKeyN('username', nusername);

下面添加；

myajax.AddKeyN('website', f.website.value);