我是 jQuery 的新手,我编写了一个简单的函数来检查每次按键的密码强度.
I'm quite new to jQuery, and I've written a simple function to check the strength of a password for each keypress.
这个想法是,每次用户输入一个字符时,都会评估内容以测试他们输入的密码的强度......我相信每个人都以前见过这些.
The idea is that every time a user enters a character, the contents is evaluated to test the strengh of the password they have entered... I'm sure everyone has seen these before.
无论如何,我使用的逻辑是没有密码以值 1 开头.当使用小写字符时,分数增加到 2.当使用数字时,分数再次增加 1,同样当使用大写字符并且密码长度为 5 个或更多字符时.
Anyhow, the logic I have used is that no password begins with a value of 1. When a lower-case character is used, the score increments to 2. When a digit is used the score increments by 1 again, same for when an uppercase character is used and when the password becomes 5 or more characters long.
每次按下一个键时,返回的都是密码强度,从 1 到 5 的值.
What is returned is the strength of the password so far as a value from 1 to 5 every time a key is pressed.
那么,关于我的问题.我完成它的方式似乎不像 jQuery 那样......几乎就像我可能刚刚完成了直接的 javascript.我也想知道我的逻辑.我做了什么或忽略了什么?比我更聪明的人有什么建议吗?
So, about my question. The way that I've done it doesn't seem very jQuery like... almost like I may as well have just done straight javascript. Also I was wondering about my logic. Have I done anything done or overlooked something? Any suggestions from smarter people than myself?
任何建议或意见将不胜感激.
Any suggestions or advice would be appreciated.
$(document).ready(function(){
$("#pass_strength").keyup(function() {
var strength = 1;
/*length 5 characters or more*/
if(this.value.length >= 5) {
strength++;
}
/*contains lowercase characters*/
if(this.value.match(/[a-z]+/)) {
strength++;
}
/*contains digits*/
if(this.value.match(/[0-9]+/)) {
strength++;
}
/*contains uppercase characters*/
if(this.value.match(/[A-Z]+/)) {
strength++;
}
alert(strength);
});
});
最好的方法是按照 TJB 的建议使用现有的插件.
The best way is to take an existing plugin as TJB suggested.
关于代码本身的问题,一个更好的方法是这样写:
As to your question about the code itself, a nicer way is to write it like that:
var pass = "f00Bar!";
var strength = 1;
var arr = [/.{5,}/, /[a-z]+/, /[0-9]+/, /[A-Z]+/];
jQuery.map(arr, function(regexp) {
if(pass.match(regexp))
strength++;
});
(已修改以纠正语法错误.)
(Modified to correct syntax errors.)
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