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      在 jQuery ajax 成功回调中创建时弹出窗口被阻止

      时间:2023-10-01
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              1. 本文介绍了在 jQuery ajax 成功回调中创建时弹出窗口被阻止的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                Google Chrome 似乎阻止了我通过 jQuery 创建的弹出窗口.经过一番调查,在 ajax 调用的成功事件中调用 window.open 似乎是一个问题.有没有解决的办法?我的 jQuery ajax 调用返回要打开的 URL.所以我有点卡住了.

                Google Chrome seems to be blocking a popup I am creating via jQuery. After some investigation, it appears to be an issue with calling window.open in the success event of an ajax call. Is there a way around this? My jQuery ajax call returns the URL to be opened. So I am bit stuck.

                如果我将 window.open 放在 ajax 调用之外,它会起作用;但是,在内部(即在成功事件中)它被阻止了.我认为这与 CONTEXT 有关,但我不确定.

                It works if I place the window.open outside the ajax call; but, inside (i.e. in the success event) it is blocked. I think it is something to do with CONTEXT but I am unsure.

                这是我所拥有的:

                     window.open("https://www.myurl.com");  // OUTSIDE OF AJAX - no problems 
                                                            // with popup
                
                     $.ajax({
                        type: "POST",
                        url: "MyService.aspx/ConstructUrl",
                        data: jsonData,
                        contentType: "application/json; charset=utf-8",
                        dataType: "json",
                        success: function(msg) {
                            // Normally loads msg.d which is the url returned from service
                            // static url below is for testing
                            window.open("https://www.myurl.com");  // THIS IS BLOCKED
                        },
                        error: function(msg) {
                            // alert(error);
                        }
                    });
                

                推荐答案

                只需在成功回调中打开新窗口即可:

                Simply open the new window in the success callback:

                 $.ajax({
                    type: "POST",
                    url: "MyService.aspx/ConstructUrl",
                    data: jsonData,
                    contentType: "application/json; charset=utf-8",
                    dataType: "json",
                    success: function(msg) {
                        window.open("https://www.myurl.com"); 
                    },
                    error: function(msg) {
                        //alert(error);
                    }
                });
                

                请注意,您可能必须为此将 $.ajax 的异步选项设置为 false,否则可能会在收到响应之前评估 $.ajax 调用之后的代码.

                Note you might have to set $.ajax's async option to false for that, otherwise the code following the $.ajax call could be evaluated before the response is received.

                这篇关于在 jQuery ajax 成功回调中创建时弹出窗口被阻止的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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