有没有办法根据设置的 NODE_ENV
指定 gulp 任务?
Is there a way to specify a gulp task depending on the NODE_ENV
that is set?
例如在我的 package.json
文件中,我有类似的内容:
For example in my package.json
file, I have something like:
"scripts": {
"start": "gulp"
}
我有多个 gulp
任务
gulp.task('development', function () {
// run dev related tasks like watch
});
gulp.task('production', function () {
// run prod related tasks
});
如果我设置NODE_ENV=production npm start
,我可以指定只运行gulp production
吗?或者有更好的方法吗?
If I set NODE_ENV=production npm start
, can I specify to only run gulp production
? Or is there a better way to do this?
在你的默认 gulp 任务中使用一个三元组,你可以有类似的东西:
Using a single ternary in your default gulp task, you can have something like:
gulp.task('default',
[process.env.NODE_ENV === 'production' ? 'production' : 'development']
);
然后您将能够在您的 package.json
中保留单个 gulp
命令并像您所说的那样使用它:
You will then be able to keep the single gulp
command in your package.json
and using this like you said:
NODE_ENV=production npm start
NODE_ENV
变量的任何其他值都将启动 development
任务.
Any other value of your NODE_ENV
variable will launch the development
task.
您当然可以使用允许多个任务的对象进行高级用法并避免 if
树地狱:
You could of course do an advanced usage using an object allowing for multiple tasks and avoiding if
trees hell:
var tasks = {
development: 'development',
production: ['git', 'build', 'publish'],
preprod: ['build:preprod', 'publish:preprod'],
...
}
gulp.task('default', tasks[process.env.NODE_ENV] || 'fallback')
请记住,当给定一组任务时,它们将并行运行.
Keep in mind that when giving an array of tasks, they will be run in parallel.
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