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      1. 如何以编程方式为 Django 中的给定模型生成 CREATE TABLE SQL 语句?

        时间:2023-10-20

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                • 本文介绍了如何以编程方式为 Django 中的给定模型生成 CREATE TABLE SQL 语句?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我需要在我的 Django 应用程序中以编程方式为给定的 unmanaged 模型生成 CREATE TABLE 语句 (managed = False)

                  I need to programmatically generate the CREATE TABLE statement for a given unmanaged model in my Django app (managed = False)

                  由于我正在处理旧数据库,因此我不想创建迁移并使用 sqlmigrate.

                  Since i'm working on a legacy database, i don't want to create a migration and use sqlmigrate.

                  ./manage.py sql 命令对此很有用,但在 Django 1.8 中已被删除

                  The ./manage.py sql command was useful for this purpose but it has been removed in Django 1.8

                  你知道任何替代方案吗?

                  Do you know about any alternatives?

                  推荐答案

                  按照建议,我发布了该案例的完整答案,问题可能暗示.

                  As suggested, I post a complete answer for the case, that the question might imply.

                  假设您有一个外部数据库表,您决定将其作为 Django 模型访问,因此将其描述为非托管模型(Meta: managed = False).稍后您需要能够在代码中创建它,例如使用本地数据库进行一些测试.显然,Django 不会对非托管模型进行迁移,因此不会在您的测试数据库中创建它.这可以使用 Django API 解决,而无需使用原始 SQL - SchemaEditor.请参阅下面更完整的示例,但作为一个简短的答案,您可以像这样使用它:

                  Suppose you have an external DB table, that you decided to access as a Django model and therefore have described it as an unmanaged model (Meta: managed = False). Later you need to be able to create it in your code, e.g for some tests using your local DB. Obviously, Django doesn't make migrations for unmanaged models and therefore won't create it in your test DB. This can be solved using Django APIs without resorting to raw SQL - SchemaEditor. See a more complete example below, but as a short answer you would use it like this:

                     from django.db import connections
                  
                     with connections['db_to_create_a_table_in'].schema_editor() as schema_editor:
                          schema_editor.create_model(YourUnmanagedModelClass)
                  

                  一个实际的例子:

                  # your_app/models/your_model.py
                  
                  from django.db import models
                  
                  class IntegrationView(models.Model):
                      """A read-only model to access a view in some external DB."""
                  
                      class Meta:
                          managed = False
                          db_table = 'integration_view'
                  
                      name = models.CharField(
                          db_column='object_name',
                          max_length=255,
                          primaty_key=True,
                          verbose_name='Object Name',
                      )
                      some_value = models.CharField(
                          db_column='some_object_value',
                          max_length=255,
                          blank=True,
                          null=True,
                          verbose_name='Some Object Value',
                      )
                  
                      # Depending on the situation it might be a good idea to redefine
                      # some methods as a NOOP as a safety-net.
                      # Note, that it's not completely safe this way, but might help with some
                      # silly mistakes in user code
                  
                      def save(self, *args, **kwargs):
                          """Preventing data modification."""
                          pass
                  
                      def delete(self, *args, **kwargs):
                          """Preventing data deletion."""
                          pass
                  

                  现在,假设您需要能够通过 Django 创建此模型,例如进行一些测试.

                  Now, suppose you need to be able to create this model via Django, e.g. for some tests.

                  # your_app/tests/some_test.py
                  
                  # This will allow to access the `SchemaEditor` for the DB
                  from django.db import connections
                  from django.test import TestCase
                  from your_app.models.your_model import IntegrationView
                  
                  class SomeLogicTestCase(TestCase):
                      """Tests some logic, that uses `IntegrationView`."""
                  
                      # Since it is assumed, that the `IntegrationView` is read-only for the
                      # the case being described it's a good idea to put setup logic in class 
                      # setup fixture, that will run only once for the whole test case
                      @classmethod
                      def setUpClass(cls):
                          """Prepares `IntegrationView` mock data for the test case."""
                  
                          # This is the actual part, that will create the table in the DB
                          # for the unmanaged model (Any model in fact, but managed models will
                          # have their tables created already by the Django testing framework)
                          # Note: Here we're able to choose which DB, defined in your settings,
                          # will be used to create the table
                  
                          with connections['external_db'].schema_editor() as schema_editor:
                              schema_editor.create_model(IntegrationView)
                  
                          # That's all you need, after the execution of this statements
                          # a DB table for `IntegrationView` will be created in the DB
                          # defined as `external_db`.
                  
                          # Now suppose we need to add some mock data...
                          # Again, if we consider the table to be read-only, the data can be 
                          # defined here, otherwise it's better to do it in `setUp()` method.
                  
                          # Remember `IntegrationView.save()` is overridden as a NOOP, so simple
                          # calls to `IntegrationView.save()` or `IntegrationView.objects.create()`
                          # won't do anything, so we need to "Improvise. Adapt. Overcome."
                  
                          # One way is to use the `save()` method of the base class,
                          # but provide the instance of our class
                          integration_view = IntegrationView(
                              name='Biggus Dickus',
                              some_value='Something really important.',
                          )
                          super(IntegrationView, integration_view).save(using='external_db')
                  
                          # Another one is to use the `bulk_create()`, which doesn't use
                          # `save()` internally, and in fact is a better solution
                          # if we're creating many records
                  
                          IntegrationView.objects.using('external_db').bulk_create([
                              IntegrationView(
                                  name='Sillius Soddus',
                                  some_value='Something important',
                              ),
                              IntegrationView(
                                  name='Naughtius Maximus',
                                  some_value='Whatever',
                              ),
                          ])
                  
                      # Don't forget to clean after
                      @classmethod
                      def tearDownClass(cls):
                          with connections['external_db'].schema_editor() as schema_editor:
                              schema_editor.delete_model(IntegrationView)
                  
                      def test_some_logic_using_data_from_integration_view(self):
                           self.assertTrue(IntegrationView.objects.using('external_db').filter(
                               name='Biggus Dickus',
                           ))
                  

                  为了使示例更完整...由于我们使用了多个数据库(defaultexternal_db),Django 将尝试在这两个数据库上运行迁移测试,到目前为止,数据库设置中没有选项可以防止这种情况发生.所以我们必须使用自定义的 DB 路由器进行测试.

                  To make the example more complete... Since we're using multiple DB (default and external_db) Django will try to run migrations on both of them for the tests and as of now there's no option in DB settings to prevent this. So we have to use a custom DB router for testing.

                   # your_app/tests/base.py
                  
                  class PreventMigrationsDBRouter:
                      """DB router to prevent migrations for specific DBs during tests."""
                      _NO_MIGRATION_DBS = {'external_db', }
                  
                      def allow_migrate(self, db, app_label, model_name=None, **hints):
                          """Actually disallows migrations for specific DBs."""
                          return db not in self._NO_MIGRATION_DBS
                  

                  以及所描述案例的测试设置文件示例:

                  And a test settings file example for the described case:

                  # settings/test.py
                  
                  DATABASES = {
                      'default': {
                          'ENGINE': 'django.db.backends.oracle',
                          'NAME': 'db_name',
                          'USER': 'username',
                          'HOST': 'localhost',
                          'PASSWORD': 'password',
                          'PORT': '1521',
                      },
                      # For production here we would have settings to connect to the external DB,
                      # but for testing purposes we could get by with an SQLite DB 
                      'external_db': {
                          'ENGINE': 'django.db.backends.sqlite3',
                      },
                  }
                  
                  # Not necessary to use a router in production config, since if the DB 
                  # is unspecified explicitly for some action Django will use the `default` DB
                  DATABASE_ROUTERS = ['your_app.tests.base.PreventMigrationsDBRouter', ]
                  

                  希望这个详细的新 Django 用户友好示例能够帮助某人并节省他们的时间.

                  Hope this detailed new Django user user-friendly example will help someone and save their time.

                  这篇关于如何以编程方式为 Django 中的给定模型生成 CREATE TABLE SQL 语句?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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