用于识别 Xcode 是否在 Mac 上运行的命令框架:cmd = "ps -ax | grep -v grep | grep Xcode"
Command framed to identify if Xcode is running on Mac: cmd = "ps -ax | grep -v grep | grep Xcode"
如果 Xcode 没有运行,那么上面的命令适用于 subprocess
模块的 Popen
方法,但会引发 CalledProcessError
与 check_output
方法.我试图通过以下代码检查stderr
,但未能获得适当的信息来理解原因.
If Xcode is not running, then above command works well with Popen
method of subprocess
module, but raises a CalledProcessError
with check_output
method. I tried to inspect the stderr
through the following code, but failed to get appropriate information to understand the reason.
from subprocess import check_output, STDOUT, CalledProcessError
psCmd = "ps -ax | grep -v grep | grep Xcode"
o = None
try:
o = check_output(psCmd, stderr=STDOUT, shell=True)
except CalledProcessError as ex:
print 'Error:', ex, o
异常信息如下:
错误:命令'ps -ax |grep -v grep |grep Xcode' 返回非零退出状态 1 无
问题:为什么上面的命令对 Popen 有效,但由于 check_output 失败?
Question: Why the above command works with Popen, but fails with check_output ?
注意:如果 Xcode 正在运行,命令对这两种方法都适用.
Note: Command works well with both approach, if Xcode is running.
check_output()
按预期工作.下面是它在 Popen()
方面的简化实现:
check_output()
works as expected. Here's its simplified implementation in terms of Popen()
:
def check_output(cmd):
process = Popen(cmd, stdout=PIPE)
output = process.communicate()[0]
if process.returncode != 0:
raise CalledProcessError(process.returncode, cmd, output=output)
return output
grep
如果没有找到任何东西,则返回 1
,也就是说,如果 Xcode 没有运行,您应该期待异常.
grep
returns 1
if it hasn't found anything i.e., you should expect the exception if Xcode is not running.
注意:如实现所示,即使发生异常也能得到输出:
Note: as the implementation shows, you can get the output even if the exception occurs:
#!/usr/bin/env python
from subprocess import check_output, STDOUT, CalledProcessError
cmd = "ps -ax | grep -v grep | grep Xcode"
try:
o = check_output(cmd, stderr=STDOUT, shell=True)
returncode = 0
except CalledProcessError as ex:
o = ex.output
returncode = ex.returncode
if returncode != 1: # some other error happened
raise
您可以改用 pgrep -a Xcode
命令(注意:以 p
开头)或使用 psutil
模块作为可移植代码:
You could probably use pgrep -a Xcode
command instead (note: starts with p
) or use psutil
module for a portable code:
#!/usr/bin/env python
import psutil # $ pip install psutil
print([p.as_dict() for p in psutil.process_iter() if 'Xcode' in p.name()])
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