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      1. python:获取频道的所有 youtube 视频网址

        时间:2023-09-02
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                  本文介绍了python:获取频道的所有 youtube 视频网址的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我想获取特定频道的所有视频网址.我认为 json 与 python 或 java 将是一个不错的选择.我可以使用以下代码获取最新视频,但是如何获取所有视频链接 (>500)?

                  I want to get all video url's of a specific channel. I think json with python or java would be a good choice. I can get the newest video with the following code, but how can I get ALL video links (>500)?

                  import urllib, json
                  author = 'Youtube_Username'
                  inp = urllib.urlopen(r'http://gdata.youtube.com/feeds/api/videos?max-results=1&alt=json&orderby=published&author=' + author)
                  resp = json.load(inp)
                  inp.close()
                  first = resp['feed']['entry'][0]
                  print first['title'] # video title
                  print first['link'][0]['href'] #url
                  

                  推荐答案

                  将 max-results 从 1 增加到你想要的任意数量,但要注意他们不建议一次调用太多,并且会将你限制在 50 (https://developers.google.com/youtube/2.0/developers_guide_protocol_api_query_parameters).

                  Increase max-results from 1 to however many you want, but beware they don't advise grabbing too many in one call and will limit you at 50 (https://developers.google.com/youtube/2.0/developers_guide_protocol_api_query_parameters).

                  相反,您可以考虑以 25 个为一组抓取数据,例如,通过更改 start-index 直到没有返回.

                  Instead you could consider grabbing the data down in batches of 25, say, by changing the start-index until none came back.

                  这是我将如何做的代码

                  import urllib, json
                  author = 'Youtube_Username'
                  
                  foundAll = False
                  ind = 1
                  videos = []
                  while not foundAll:
                      inp = urllib.urlopen(r'http://gdata.youtube.com/feeds/api/videos?start-index={0}&max-results=50&alt=json&orderby=published&author={1}'.format( ind, author ) )
                      try:
                          resp = json.load(inp)
                          inp.close()
                          returnedVideos = resp['feed']['entry']
                          for video in returnedVideos:
                              videos.append( video ) 
                  
                          ind += 50
                          print len( videos )
                          if ( len( returnedVideos ) < 50 ):
                              foundAll = True
                      except:
                          #catch the case where the number of videos in the channel is a multiple of 50
                          print "error"
                          foundAll = True
                  
                  for video in videos:
                      print video['title'] # video title
                      print video['link'][0]['href'] #url
                  

                  这篇关于python:获取频道的所有 youtube 视频网址的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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