在需要或不需要用括号括起来的元组时,是否有精确定义的引用?
Is there a reference somewhere defining precisely when enclosing tuples with parentheses is or is not required?
这是一个最近让我吃惊的例子:
Here is an example that surprised me recently:
>>> d = {}
>>> d[0,] = 'potato'
>>> if 0, in d:
File "<stdin>", line 1
if 0, in d:
^
SyntaxError: invalid syntax
使用逗号标记创建元组的表达式组合称为 expression_list
.运算符优先级的规则不包括表达式列表;这是因为表达式列表本身不是表达式;括在括号中时它们成为表达式.
The combining of expressions to create a tuple using the comma token is termed an expression_list
. The rules of operator precedence do not cover expression lists; this is because expression lists are not themselves expressions; they become expressions when enclosed in parentheses.
因此,在 Python 中语言语法明确允许的任何地方都允许使用未封闭的 expression_list
,但 不允许其中 expression
为这是必需的.
So, an unenclosed expression_list
is allowed anywhere in Python that it is specifically allowed by the language grammar, but not where an expression
as such is required.
例如if语句的语法如下:
if_stmt ::= "if" expression ":" suite
( "elif" expression ":" suite )*
["else" ":" suite]
因为引用了产生式 expression
,所以不允许未封闭的 expression_list
作为 if
语句的主题.但是,for 语句 接受 expression_list
:
Because the production expression
is referenced, unenclosed expression_list
s are not allowed as the subject of the if
statement. However, the for statement accepts an expression_list
:
for_stmt ::= "for" target_list "in" expression_list ":" suite
["else" ":" suite]
所以以下是允许的:
for x in 1, 2, 3:
print(x)
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