我有一个名为 data
的元组列表:
I have a list of tuples named data
:
data = [('A', 2),
('B', 2), ('B', 4), ('B', 6), ('B', 8), ('B', 6), ('B', 4), ('B', 3),
('C', 10), ('C', 10), ('C', 10),
('D', 12),
('E', 12),
('F', 10), ('F', 8), ('F', 6)]
average = []
我想要每个相同字母的平均值:
I would like an average of the values for each same letter:
预期输出:
average = [('A', 2), ('B', 5), ('C', 10), ('D', 12), ('E', 12), ('F', 8)]
试试 groupby
from itertools import groupby
data_ = [(n,[i[1] for i in g]) for n,g in groupby(data, key = lambda x:x[0])]
result = [(i,float(sum(j))/float(len(j))) for i,j in data_]
结果
[('A', 2.0),
('B', 4.714285714285714),
('C', 10.0),
('D', 12.0),
('E', 12.0),
('F', 8.0)]
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