list.sort()
对列表进行排序并替换原始列表,而 sorted(list)
返回列表的排序副本,而不更改原始列表.
list.sort()
sorts the list and replaces the original list, whereas sorted(list)
returns a sorted copy of the list, without changing the original list.
list.sort()
执行后列表能否恢复为未排序状态?list.sort()
has been performed?sorted()
返回一个 new 排序列表,不影响原始列表.list.sort()
对列表进行 就地 排序,改变列表索引,并返回 None
(与所有就地操作一样).
sorted()
returns a new sorted list, leaving the original list unaffected. list.sort()
sorts the list in-place, mutating the list indices, and returns None
(like all in-place operations).
sorted()
适用于任何可迭代对象,而不仅仅是列表.字符串、元组、字典(你会得到键)、生成器等,返回一个包含所有元素的列表,排序.
sorted()
works on any iterable, not just lists. Strings, tuples, dictionaries (you'll get the keys), generators, etc., returning a list containing all elements, sorted.
当你想要改变列表时使用list.sort()
,当你想要一个新的排序对象返回时使用sorted()
.sorted() 当你想对一个可迭代的东西进行排序时,使用 还.
Use list.sort()
when you want to mutate the list, sorted()
when you want a new sorted object back. Use sorted()
when you want to sort something that is an iterable, not a list yet.
对于列表,list.sort()
比 sorted()
快,因为它不必创建副本.对于任何其他可迭代对象,您别无选择.
For lists, list.sort()
is faster than sorted()
because it doesn't have to create a copy. For any other iterable, you have no choice.
不,您无法检索原始位置.一旦你调用了 list.sort()
,原来的顺序就消失了.
No, you cannot retrieve the original positions. Once you called list.sort()
the original order is gone.
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