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        多次克隆 NumPy 数组

        时间:2023-08-29
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                  本文介绍了多次克隆 NumPy 数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我将一张图片加载到一个 numpy 数组中,需要以 2 个不同的阈值对其图片进行阈值处理.

                  I loaded a picture into a numpy array and need to threshold it picture at 2 different thresholds.

                  import numpy as np
                  import cv2
                  
                  cap = cv2.Videocapture(0)
                  _,pic = cap.read()
                  pic1 = pic
                  pic2 = pic
                  
                  pic1[pic1 > 100] = 255
                  pic2[pic2 > 200] = 255
                  

                  当我只希望他们修改 pic1 和 pic2 时,此代码将始终编辑 pic

                  This code will always edit pic when I only want them to modify pic1 and pic2

                  推荐答案

                  在python中,对象和变量是有区别的.变量是分配给对象的名称;并且一个对象在内存中可以有多个名称.

                  In python, there is a difference between an object and a variable. A variable is name assigned to an object; and an object can have more than one name in memory.

                  通过 pic1 = pic;pic2 = pic,您将 same 对象分配给多个不同的变量名称,因此您最终会修改同一个对象.

                  By doing pic1 = pic; pic2 = pic, You're assigning the same object to multiple different variable names, so you end up modifying the same object.

                  你想要的是使用 np.ndarray.copy-

                  pic1 = pic.copy()
                  pic2 = pic.copy()
                  

                  或者,非常相似,使用 np.copy

                  Or, quite similarly, using np.copy

                  pic1, pic2 = map(np.copy, (pic, pic))
                  

                  这种语法实际上使 真的 很容易克隆 pic 任意多次:

                  This syntax actually makes it really easy to clone pic as many times as you like:

                  pic1, pic2, ... picN = map(np.copy, [pic] * N)
                  

                  其中 N 是您要创建的副本数.

                  Where N is the number of copies you want to create.

                  这篇关于多次克隆 NumPy 数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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