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    1. 无法将列表转换为集合,引发“unhashable type: 'list'"错误

      时间:2023-07-24
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              1. 本文介绍了无法将列表转换为集合,引发“unhashable type: 'list'"错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                所以我正在尝试查找列表的所有子列表,这就是我现在所拥有的.我是 Python 新手,我不明白为什么Q3_ans=set(ans)"会引发错误.我曾尝试将列表转换为之前的设置,它可以工作.

                So I'm trying to find all sub-lists of a list and here is what I have now. I'm new to Python and I don't understand why " Q3_ans=set(ans)" raises an error. I've tried to convert a list to set before and it works.

                def f2(seq):
                    '''
                    This is the base case of the recursion from function all_sublists
                    '''
                    assert len(seq)==2
                    assert isinstance(x,list)
                    a,b=seq
                    return [[a],[b],[a,b]]
                
                
                def all_sublists(x):
                    '''
                    This function will generate all of the sublists of a list, not including the empty one, using recursion
                    '''
                    assert isinstance(x,list)
                    ans=[]
                    for i in range(0,len(x)-1):
                        for j in range(1,len(x)):
                            temp=[x[i],x[j]]
                            temp=[f2(temp)]
                            ans.extend(temp)
                    Q3_ans=set(ans) 
                    return Q3_ans
                

                这是我运行代码时的错误y=[1,2,3,4,5]

                Here is the error when I run my code y=[1,2,3,4,5]

                all_sublists(y)
                ---------------------------------------------------------------------------
                TypeError                                 Traceback (most recent call last)
                <ipython-input-108-f8b1bb0a7001> in <module>
                ----> 1 all_sublists(y)
                
                <ipython-input-106-84f4f752e98e> in all_sublists(x)
                     10             temp=[f2(temp)]
                     11             ans.extend(temp)
                ---> 12     Q3_ans=set(ans)
                     13     return Q3_ans
                
                TypeError: unhashable type: 'list'
                

                推荐答案

                这是问题的本质:

                >>> set([[["a"],["b"],["a","b"]]])
                Traceback (most recent call last):
                  File "<stdin>", line 1, in <module>
                TypeError: unhashable type: 'list'
                

                那么,这是什么意思?

                set([iterable])

                返回一个新的 set ... 对象,其元素取自可迭代对象.集合的元素必须是可散列的.

                Return a new set ... object whose elements are taken from iterable. The elements of a set must be hashable.

                可散列

                一个对象是可哈希的,如果它有一个永远不会改变的哈希值在其生命周期内(它需要一个 __hash__() 方法),并且可以与其他对象相比(它需要一个 __eq__() 方法).可散列比较相等的对象必须具有相同的哈希值.

                An object is hashable if it has a hash value which never changes during its lifetime (it needs a __hash__() method), and can be compared to other objects (it needs an __eq__() method). Hashable objects which compare equal must have the same hash value.

                Hashability 使对象可用作字典键和集合成员,因为这些数据结构在内部使用哈希值.

                Hashability makes an object usable as a dictionary key and a set member, because these data structures use the hash value internally.

                所有 Python 的不可变内置对象都是可散列的;可变的容器(例如列表或字典)不是.

                All of Python’s immutable built-in objects are hashable; mutable containers (such as lists or dictionaries) are not.

                这里的关键字是可变

                The keywords here are mutable

                可变对象可以改变它们的值,但保留它们的 id().

                Mutable objects can change their value but keep their id().

                不可变

                具有固定值的对象.不可变对象包括数字,字符串和元组.这样的对象是不能改变的.一个新对象有如果必须存储不同的值,则创建.他们玩在需要恒定哈希值的地方发挥重要作用,例如例如作为字典中的键.

                An object with a fixed value. Immutable objects include numbers, strings and tuples. Such an object cannot be altered. A new object has to be created if a different value has to be stored. They play an important role in places where a constant hash value is needed, for example as a key in a dictionary.

                因此,您不能将 list 用作 set 元素.tuple 可以工作:

                So, you can't use a list as set element. A tuple would work:

                >>> set([(("a"),("b"),("a","b"))])
                {('a', 'b', ('a', 'b'))}
                

                这篇关于无法将列表转换为集合,引发“unhashable type: 'list'"错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

                上一篇:将数字 1 添加到集合中没有效果 下一篇:删除二维数组中无序重复项最省时的方法是什么?

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