所以我正在尝试查找列表的所有子列表,这就是我现在所拥有的.我是 Python 新手,我不明白为什么Q3_ans=set(ans)"会引发错误.我曾尝试将列表转换为之前的设置,它可以工作.
So I'm trying to find all sub-lists of a list and here is what I have now. I'm new to Python and I don't understand why " Q3_ans=set(ans)" raises an error. I've tried to convert a list to set before and it works.
def f2(seq):
'''
This is the base case of the recursion from function all_sublists
'''
assert len(seq)==2
assert isinstance(x,list)
a,b=seq
return [[a],[b],[a,b]]
def all_sublists(x):
'''
This function will generate all of the sublists of a list, not including the empty one, using recursion
'''
assert isinstance(x,list)
ans=[]
for i in range(0,len(x)-1):
for j in range(1,len(x)):
temp=[x[i],x[j]]
temp=[f2(temp)]
ans.extend(temp)
Q3_ans=set(ans)
return Q3_ans
这是我运行代码时的错误y=[1,2,3,4,5]
Here is the error when I run my code y=[1,2,3,4,5]
all_sublists(y)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-108-f8b1bb0a7001> in <module>
----> 1 all_sublists(y)
<ipython-input-106-84f4f752e98e> in all_sublists(x)
10 temp=[f2(temp)]
11 ans.extend(temp)
---> 12 Q3_ans=set(ans)
13 return Q3_ans
TypeError: unhashable type: 'list'
这是问题的本质:
>>> set([[["a"],["b"],["a","b"]]])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
那么,这是什么意思?
set([iterable])
一个>
返回一个新的 set ... 对象,其元素取自可迭代对象.集合的元素必须是可散列的.
Return a new set ... object whose elements are taken from iterable. The elements of a set must be hashable.
可散列
一个对象是可哈希的,如果它有一个永远不会改变的哈希值在其生命周期内(它需要一个 __hash__()
方法),并且可以与其他对象相比(它需要一个 __eq__()
方法).可散列比较相等的对象必须具有相同的哈希值.
An object is hashable if it has a hash value which never changes during its lifetime (it needs a
__hash__()
method), and can be compared to other objects (it needs an__eq__()
method). Hashable objects which compare equal must have the same hash value.
Hashability 使对象可用作字典键和集合成员,因为这些数据结构在内部使用哈希值.
Hashability makes an object usable as a dictionary key and a set member, because these data structures use the hash value internally.
所有 Python 的不可变内置对象都是可散列的;可变的容器(例如列表或字典)不是.
All of Python’s immutable built-in objects are hashable; mutable containers (such as lists or dictionaries) are not.
这里的关键字是可变
The keywords here are mutable
可变对象可以改变它们的值,但保留它们的 id().
Mutable objects can change their value but keep their id().
和 不可变
具有固定值的对象.不可变对象包括数字,字符串和元组.这样的对象是不能改变的.一个新对象有如果必须存储不同的值,则创建.他们玩在需要恒定哈希值的地方发挥重要作用,例如例如作为字典中的键.
An object with a fixed value. Immutable objects include numbers, strings and tuples. Such an object cannot be altered. A new object has to be created if a different value has to be stored. They play an important role in places where a constant hash value is needed, for example as a key in a dictionary.
因此,您不能将 list
用作 set
元素.tuple
可以工作:
So, you can't use a list
as set
element. A tuple
would work:
>>> set([(("a"),("b"),("a","b"))])
{('a', 'b', ('a', 'b'))}
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