我想将 python 脚本的子进程的标准输出和标准输入定向到同一个文件中.我不知道如何使两个来源的线条可区分?(例如,在 stderr 中的行前加上感叹号.)
I would like to direct a python script's subprocess' stdout and stdin into the same file. What I don't know is how to make the lines from the two sources distinguishable? (For example prefix the lines from stderr with an exclamation mark.)
在我的特殊情况下,不需要实时监控子进程,正在执行的 Python 脚本可以等待其执行结束.
In my particular case there is no need for live monitoring of the subprocess, the executing Python script can wait for the end of its execution.
tsk = subprocess.Popen(args,stdout=subprocess.PIPE,stderr=subprocess.STDOUT)
subprocess.STDOUT
是一个特殊的标志告诉 subprocess 将所有 stderr 输出路由到 stdout,从而组合您的两个流.
subprocess.STDOUT
is a special flag that tells subprocess to route all stderr output to stdout, thus combining your two streams.
顺便说一句,select 在 Windows 中没有 poll().subprocess 只使用文件句柄号,不会调用你的文件输出对象的 write 方法.
btw, select doesn't have a poll() in windows. subprocess only uses the file handle number, and doesn't call your file output object's write method.
要捕获输出,请执行以下操作:
to capture the output, do something like:
logfile = open(logfilename, 'w')
while tsk.poll() is None:
line = tsk.stdout.readline()
logfile.write(line)
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