我正在制作一个 Discord Bot，它可以做各种事情，包括对提到该机器人的人做出反应，以及对某些用户在某个频道中所说的话做出反应.我的代码(为清楚起见而缩短)是:
I am making a Discord Bot that does various things, including reacting to the person who mentions the bot and reacting to things certain users say in a certain channel. My code (shortened for clarity) is:
BOT = os.getenv('DISCORD_BOT_MENTION')
CHANNEL = os.getenv('DISCORD_CHANNEL')
USER1 = os.getenv('DISCORD_USER1_ID')
USER2 = os.getenv('DISCORD_USER2_ID')
@bot.event
async def on_message(message):
content = message.content # Did bot get mentioned?
channel = message.channel # Where was the bot mentioned
channel_ID = message.channel.id #
user = message.author.name # Who mentioned the bot
user_ID = message.author.id
if user == client.user:
return
elif BOT in content:
brankos_responses = [
"Hello",
"Hi",
]
weights_responses = [
15,
10,
]
response = random.choices(brankos_responses, weights_responses, k = 1)
await asyncio.sleep(0.7) # Wait 0.7s before answering
await channel.send(response[0])
elif channel_ID == int(CHANNEL):
if user_ID == int(USER_ID_1):
brankos_responses = [
"Test Message 1 for User 1 in Channel",
"Test Message 2 for User 1 in Channel",
]
response = random.choice(brankos_responses)
await channel.send(response)
if user_ID == int(USER_id_2):
brankos_responses = [
"Test Message 1 for User 2 In Channel",
"Test Message 2 for User 2 in Channel",
]
response = random.choice(brankos_responses)
await channel.send(response)
else:
return
await bot.process_commands(message)
但是我发现，如果您向机器人发送垃圾邮件，或者如果用户 1 和 2 在频道中交谈，它会继续回复，我想限制这种情况.例如，在使用 @commands.cooldown(1, 3600, commands.BucketType.user) 很容易的 discord.py 命令中，但是我拥有的不是命令，因此不能在这里使用.
However I found that if you spam @ the bot or if the Users 1 and 2 talk in Channel, it will keep giving replies, and I would like to limit that.
In discord.py commands that's easy with @commands.cooldown(1, 3600, commands.BucketType.user) for example, however what I have is not a command, so it can't be used here.
我认为我可以让机器人休眠(使用 await asyncio)，当它注意到频道中来自一位用户的消息时，然后当该人 5 秒钟内没有说任何话时，它会运行代码并发送 1 个回复，但这只会导致所有回复堆积起来，并在几秒钟后发送.
I thought that I could just have the bot sleep (with await asyncio), when it notices a message in the CHANNEL from one of the users, and then when the person has not said anything for 5 seconds that it would run the code and send 1 reply, however that just results in all the responses piling up and all being send after a few seconds.
所以我的问题是:如何限制机器人的回复数量?
So my question is: How can I limit the amount of replies the bot gives?
现在我正在尝试这个:
user_list = [
int(USER1_ID),
int(USER2_ID),
int(USER3_ID),
int(USER4_ID),
]
messages = 0 # Define the count
if user_ID in user_list:
messages += 1 # Add one to count
print(messages)
if messages > 5: # If messages is more than 5, execute code
response = random.choice(brankos_responses)
await channel.send(response)
messages = 0 # Reset count
但是因为它再次运行，它再次重置为messages = 1，如果我将messages = 0放在函数之外它不起作用.
But because it runs again, it resets to messages = 1 again, and if I put messages = 0 outside the function it does not work.
如果你的目的纯粹是为了让机器人在时间上有一个冷却时间，那么你可以这样做:
If your intention is purely to have a cooldown on the bot timewise, then you could do something such as:
class StackOverflow(commands.Cog):
def __init__(self, client):
self.client = client
self.last_timeStamp = datetime.datetime.utcfromtimestamp(0)
@commands.Cog.listener()
async def on_message(self, message):
time_difference = (datetime.datetime.utcnow() - self.last_timeStamp).total_seconds()
if time_difference < 120:
# Don't do anything and return
return
else:
#Do things
self.last_timeStamp = datetime.datetime.utcnow()
这是在 Cog 中完成的，因此如果您想在 Cog 之外使用它，可能需要进行更改.如果您只想计算消息的数量，那么只需有一个 int 变量，每条消息递增它并更改 if 语句.
This was done in a Cog, so you might have to make alterations if you want to use it outside a Cog. If you wanted to just count the number of messages, then just have a int variable, increment it every message and change the if statement.
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