对于 1970-01-01 之前的日期，Windows 上 datetime timestamp() 的解决方法

问题描述

我目前正在尝试通过将日期转换为时间戳来在数据集中生成数字特征.如果在 Mac 上运行，它可以完美运行，在 Windows 上它会抛出:

I am currently trying to generate numerical features in a dataset by converting the dates to timestamps. If run on Mac, it works flawlessly, on Windows it throws an:

OS Error: [Errno 22] Invalid argument

这可能是由于 Windows 不支持 unix 时间戳1970-01-01 之前.我的日期从 1955 年开始.这是我的代码:

which is probably due to Windows not supporting unix timestamps from before 1970-01-01. I have dates from 1955 upwards. Here is my code:

import time
import datetime

current_timestamp = time.time()
df.loc[:, "FEATURE_num"] = df["FEATURE"].apply(lambda d: datetime.datetime.strptime(d, '%Y-%m-%d').timestamp() if isinstance(d, str) else current_timestamp)

我在某处看到有人建议使用 datetime.timedelta()，但我不知道如何集成它.

I somewhere saw suggested to maybe use datetime.timedelta(), but I couldn't figure out how to integrate it.

推荐答案

你可以通过(隐式)使用 datetime.timedelta 计算一个公历"时间戳适用于从 1582 年 10 月 15 日到现在(或您想使用的其他纪元")的日期.

You could do it by (implicitly) using datetime.timedelta to calculate a "Gregorian" timestamp that would be valid for dates from 1582-Oct-15 to the present (or some other "epoch" you would like to use).

正如函数的文档字符串所示，默认情况下，日期字符串将使用 '%Y-%m-%d' strptime-like 格式字符串参数，但可以覆盖.

As the function's docstring indicates, date strings will, by default, be parsed using a '%Y-%m-%d' strptime-like format string parameter, but that can be overridden.

from datetime import datetime


GREGORIAN_EPOCH = datetime.strptime('1582-10-15', '%Y-%m-%d')


def gregorian_timestamp(date, format='%Y-%m-%d'):
    """ Calculate timestamp using start of Gregorian calender as epoch.

        The date parameter can be either a string or a datetime.datetime
        object. Strings will be parsed using the '%Y-%m-%d' format by default
        unless a different one is specfied via the optional format parameter.
    """
    try:
        date = datetime.strptime(date, format)
    except TypeError:
        pass
    return (date - GREGORIAN_EPOCH).total_seconds()  # The timedelta in seconds.


if __name__ == '__main__':

    current_date = datetime.now()
    timestamp = gregorian_timestamp(current_date)
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 13768250461.136208

    timestamp = gregorian_timestamp('1970-01-01')
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 12219292800.0

    timestamp = gregorian_timestamp('1955-02-28')
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 11750918400.0

    timestamp = gregorian_timestamp('1582-10-15')
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 0.0

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